Python Forum

Its the first time I'm using pathlib. Any reference to it seems to hang. Is it something to so with permissions ?
I'm working under my home directory, so there shouldn't be an issue.

Output:
bluefrog@pk:~/sample_code$ ls -ltr
total 48
drwxr-xr-x  2 bluefrog bluefrog 4096 May 22  2017 db_release
drwxr-xr-x  3 bluefrog bluefrog 4096 Nov  7  2017 bash
drwxr-xr-x  3 bluefrog bluefrog 4096 Apr 21 21:28 c++
drwxrwxr-x 28 bluefrog bluefrog 4096 Sep 23 12:10 python
drwxr-xr-x  3 bluefrog bluefrog 4096 Sep 23 15:34 python_tests
drwxr-xr-x  5 bluefrog bluefrog 4096 Sep 23 15:55 pthon_docs
bluefrog@pk:~/sample_code$ whoami
bluefrog

The code is quite simple:

import pathlib
print("Present working directory : {}".format(pathlib.Path.cwd()))
rootdir = pathlib.Path("/home/bluefrog/sample_code/python")
for path in rootdir.glob("./*.py"):
    print(path, path.stat().st_size, path.parent)

Any ideas ?

if /home/bluefrog/sample_code/python is your source directory, and the program you show is in that path, you can use:

rootdir = Path('.')

here's some stuff you can do:

import os
from pathlib import Path

#make sure you're in source directory:
os.chdir(os.path.dirname(__file__))
rootdir = Path('.')

# to  get your python files:
pyfiles = [filename for filename in rootdir.iterdir() if filename.suffix == '.py']
# some stuff with first file
filename = pyfiles[0]
print(f'fullpath: {filename.resolve()}')
print(f'program name: {filename.name}')
print(f'path components: {filename.parts}')
# show code of first file:
print('\n\n\n')
with filename.open() as fp:
    for line in fp:
        print(line)

I am not sure that it's an issue, but I would replace "./*.py" with '*.py'. ./ is redundant

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PS I think you need rglob or glob(*/*.py')