How do you iterate over arguments passed to a script? I'm trying to use sys.argv as shown below, which does not work.
-Thanks
print 'Number of arguments:', len(sys.argv), 'arguments.'
print 'Argument List:', str(sys.argv)
for jpgfile in str(sys.argv):
print(jpgfile)
How does it not work? It works for me, although note that looping over a string loops over each character in the string. You did import sys, right? It's not in your code.
(Nov-20-2018, 03:20 AM)ichabod801 Wrote: [ -> ]How does it not work? It works for me, although note that looping over a string loops over each character in the string. You did import sys, right? It's not in your code.
Here is what I got for output. How do I print each individual argument?
Output:
im-datestamp.py aaa bbb
Number of arguments: 3 arguments.
Argument List: ['./im-datestamp.py', 'aaa', 'bbb']
[
'
.
/
i
m
-
d
a
t
e
s
t
a
m
p
.
p
y
'
,
'
a
a
a
'
,
'
b
b
b
'
]
>>> type(sys.argv)
<class 'list'>
Iterating over a string returns each letter.
for element in sys.argv: should do it.
(Nov-20-2018, 07:01 AM)wavic Wrote: [ -> ]>>> type(sys.argv)
<class 'list'>
Iterating over a string returns each letter. for element in sys.argv: should do it.
Thanks, I wound up using this which eliminates the script name in [0]:
for jpgfile in sys.argv[1:]:
Exactly!
Look at the
argparse module. It allows much more flexibility and control over the arguments.