Python Forum

Hi There,
I've prepared a piece of code, which intention is to log as a root user.
I can't use "sudo" method because that is not existing on the system that i want to control and logging directly as "root" is impossible. My idea is to log as a "admin" user and then use "su" command to switch to "root" user.

Code:

from fabric import Connection
from invoke import Responder

sudopass = Responder(pattern=r'Password:', response='adminPassword\n')

with Connection('192.168.0.106', user="admin", port=22, connect_kwargs={"password": "admin"}) as dss:
    command = "uname -s"
    print("Response on {} is: {}".format(command, dss.run(command)))
    command = "whoami"
    print("Response on {} is: {}".format(command, dss.run(command)))
    command = "su"
    print("Response on {} is after executing su command: {}".format(command,
                                                                    dss.run(command, pty=True, watchers=[sudopass])))
    command = "whoami"
    print("Response on {} is: {}".format(command, dss.run(command)))
print("Script end")

Output:

Output:
Linux
Response on uname -s is: Command exited with status 0.
=== stdout ===
Linux

(no stderr)
dssadmin
Response on whoami is: Command exited with status 0.
=== stdout ===
dssadmin

(no stderr)
Password: 
/home/dssadmin # 

As you can see script got stuck after sending "su" command. Any ideas how to solve that? Thanks for help in advance:)

===========================================================================
Python 3.7
Fabric 2.4.0

Looks like it's maybe still waiting for the password? Maybe try changing the pattern to include trailing whitespace: r"Password:\s*?"

No no, it was logged properly for sure. I can see that after sending "su" command it is now in /home/dssadmin directory as it should be after successful loggin. Sorry, i should mention that in my post:)

According to me it's waiting for some exit code or sometthing

So far i've this:

So far i've this:
sudopass = Responder(pattern=r'Password:', response='admin__password\n')

def su(connection, command) -> int:
    return connection.run(f"su -c '{command}'", pty=True, watchers=[sudopass])

with Connection('192.168.0.106', user="dssadmin", port=22, connect_kwargs={"password": "password"}) as ssh_connection:
    command = "uname -s"
    print("Response on {} is: {}".format(command, ssh_connection.run(command)))
    command = "whoami"
    print("Response on {} is: {}".format(command, ssh_connection.run(command)))
    command = "opkg update"
    print("Response on {} is after executing su command: {}".format(command, su(ssh_connection, command)))
    command = "opkg install rescue-utils"
    print("Response on {} is after executing su command: {}".format(command, su(ssh_connection, command)))
    command = "whoami"
    print("Response on {} is: {}".format(command, su(dss, command)))
print("Script end")

Not exactly what i needed but working fine