Is there a build it method to do the following?
num = 001
num += 1
print(str(num))
result: 002
currently I get an 'Invalid token' error with 001 as a variable
I'm just looking for a way to count 001, 002 - 999. Rather not reinvent the wheel if something already exists.
Thanks!
Numbers with leading zeros are illegal, because doesn't want you to get confused about whether or not they're octal numbers (which are, instead, defined with a leading 0o in python). If you remove the leading zeros, your code will work fine.
(Feb-06-2019, 09:25 PM)jmair Wrote: [ -> ]I'm just looking for a way to count 001, 002 - 999.
Use string formatting
f-string is what you should use need 3.6+,version before that use
format().
for i in range(1,21):
print(f"{i:03}") Output:
001
002
003
004
005
006
007
008
009
010
011
012
013
014
015
016
017
018
019
020
Sometimes, e.g. when it is needed to create/(or load) numbered files, you need to create strings
such as '001', '002' etc. To get this you could use
.format method, e.g.
"{:03d}".format(4)Output:
'004'
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P.S.
Too late, the same answer already exists...
That's exactly what I needed! Thank you!