Python Forum

I have the following code:

from PyQt5.QtWidgets import *
from PyQt5.QtGui import *
from PyQt5.QtCore import *
from gui import Ui_mainWindow
import acquisition 

class Logic(QtWidgets.QMainWindow, Ui_mainWindow):
    def __init__(self, *args, **kwargs):
        super(Logic, self).__init__(*args, **kwargs)
        self.setupUi(self)
        ###SIGNALS###
        self.actionExit.triggered.connect(self.closeEvent)
        self.actionExit_2.triggered.connect(self.closeEvent)
        self.startScan.clicked.connect(self.startScan)
        self.show()
    def closeEvent(self, event):
        buttonReply = QtWidgets.QMessageBox.question(self, "Exit", "Are you sure want to quit?",
                QtWidgets.QMessageBox.Yes | QtWidgets.QMessageBox.No, QtWidgets.QMessageBox.No)
        if buttonReply == QtWidgets.QMessageBox.Yes:
            sys.exit(app.exec_())
        else:
            event.ignore()

    def startScan(self):
        acquisition.main()

if __name__ == "__main__":
    app = QApplication([])
    app.setApplicationName("xxxx")
    window = Logic()
    app.exec_()

Which returns:

TypeError: argument 1 has unexpected type 'QPushButton'

whenever ran. I have read that using

self.startScan.clicked.connect(lambda:self.startScan)

can alleviate some of these TypeErrors, but for me, the program will simply close if I use the startScan pushbutton.

acquisition.main() returns a matplotlib plot of some data from an oscilloscope. This plot appears perfectly fine when acquisition.main() is called in any other way.

How can I fix this?

Doh! There was a naming error. Problem solved.

        self.startScan.clicked.connect(self.startScan)

Should be:

        self.startScan.clicked.connect(self.beginScan)

and the startScan(self) function should be renamed to beginScan(self)

sys.exit(app.exec_())

As the app is executed only once, this line should only appear at the end of your program (instead of app.exec_()). To override the closeEvent, use event.accept() instead.

lmsavk

Alfalfa