Python Forum

if using python 3.7+ you can use order-preserving feature of dicts. Before 3.6 dicts were unordered. In 3.6. order was preserved as implementation feature (should not be relied upon)

import itertools as it

# assume using python 3.7+
my_dict = {'item1':['A', 'B'], 'item2':['C', 'D'], 'item3':['E','F']}
combinations = it.product(*my_dict.values())
for i, item in enumerate(combinations):
    print(f'array {i}:')
    for key, value in zip(my_dict.keys(), item):
        print(f'\t{key} ==> {value}')

alternative approach would be to transform your dict

import itertools as it

# assume using python 3.7+
my_dict = {'item1':['A', 'B'], 'item2':['C', 'D'], 'item3':['E','F']}
my_list = [[(key, value2) for value2 in value] for key, value in my_dict.items()]
combinations = it.product(*my_list)
for i, item in enumerate(combinations):
    print(f'array {i}:')
    for key, value in item:
        print(f'\t{key} ==> {value}')

in both cases output is

Output:
array 0:
        item1 ==> A
        item2 ==> C
        item3 ==> E
array 1:
        item1 ==> A
        item2 ==> C
        item3 ==> F
array 2:
        item1 ==> A
        item2 ==> D
        item3 ==> E
array 3:
        item1 ==> A
        item2 ==> D
        item3 ==> F
array 4:
        item1 ==> B
        item2 ==> C
        item3 ==> E
array 5:
        item1 ==> B
        item2 ==> C
        item3 ==> F
array 6:
        item1 ==> B
        item2 ==> D
        item3 ==> E
array 7:
        item1 ==> B
        item2 ==> D
        item3 ==> F

This is just basic example, build upon it to get output in desired format

This is great! Thank you very much!