Python Forum

Hello all,
Excuse my complete lack of knowledge and "newbie-ness" as it has only been a few hours since I started my already rocky road to understanding Python.
I am going through some beginner's tutorials available on web and came up with "identification"-type of codes below:

The "ID number" or "idn" has to be a number between 0 and 10.

print("What is your ID number, " + str(name) + "?", end="  ")
idn=input()
while True:
    if int(idn) > 10 or int(idn) < 0:
        print("     ERROR: the ID number is a number between 0 to 10.", end="  ")
        idn=input()
        continue
    else:
        print("Thank you, no. " + str(idn))
        input()
        break

The code seemed to be working fine, but when I just got curious and entered a character/alphabet/word instead of a number, it gave me an error message. I'd like to show "ERROR: ID is a number, not a character," if a character/word is entered. Here is my try, but it has been unsuccessful so far.

print("What is your ID number, " + str(name) + "?", end="  ")
idn=input()
while True:
    if int(idn) > 10 or int(idn) < 0:
        print("     ERROR: the ID number is a number between 0 to 10.", end="  ")
        idn=input()
        continue
    if idn=str:
        print("     ERROR: ID is a number, not a character,", end="  ")
        idn=input()
        continue
    else:
        print("Thank you, no. " + str(idn))
        input()
        break

That "if idn=str:" is what I am struggling with. How can I set up that if-command? Thank you for your time! I'd really appreciate any advice!

helplessnoobb Wrote:it gave me an error message.

This is what you need to concentrate on. Python's error messages usually contain critical information about how to solve the issue.

After idn = input(), the value of idn is necessarily of type str which you can check with print(isinstance(idn, str)), which should print True. The best thing to do here is to convert to int and print an error if it is not possible

while True
    idn = input("What is your ID number? ")
    try:
        n = int(idn):
    except ValueError:
        print("Please enter a number, not", repr(idn))
        continue
    if n in range(11):
        print('Thank you, your ID number is ', n)
        break
    else:
        print('Bad value, try again')
        continue

You have to check directly after idn=input() what you get back so what is idn.
Your "if idn=str:" is complete nonsense, you really should work through a Python tutorial.