Python Forum

Hello everyone, that's my first time on this forum, but maybe not the last:

I have a problem, i want to create a table in a postgreSQL DB that i created. When i launch my program to create this table, i recieve a psycopg2.Operationalerror with no information about this error. Maybe someone can help me ?
Thank you very much.

import psycopg2
def create_table():
    conn=psycopg2.connect("dbname='DB1' user='postgres' password='shakD6yc' host='localhost' port='5432'")   
    cur=conn.cursor()      
    cur.execute("CREATE TABLE IF NOT EXISTS store (item TEXT, quantity INTEGER, price REAL)") 
    conn.commit()
    conn.close()
  
create_table()    

And this is what appears in my console when i launch:

Error:
Traceback (most recent call last):
  File "C:\Users\Yonathan\source\repos\PostgreSQL - Python\PostgreSQL - Python\PostgreSQL___Python.py", line 60, in <module>
    create_table()
  File "C:\Users\Yonathan\source\repos\PostgreSQL - Python\PostgreSQL - Python\PostgreSQL___Python.py", line 8, in create_table
    conn=psycopg2.connect("dbname='DB1' user='postgres' password='shakD6yc' host='localhost' port='5432'")
  File "C:\Users\Yonathan\Anaconda3\lib\site-packages\psycopg2\__init__.py", line 126, in connect
    conn = _connect(dsn, connection_factory=connection_factory, **kwasync)
psycopg2.OperationalError

Error shows that it either couldn't connect, or perhaps a connection timed out.

the parameters have to be separated by ,