Python Forum

Morning All,
i'm trying to write code to use requests.post() but it keeps skipping the try and printing 'Error' with one particular line.

try:
    url = http:\\11.11.11.11    # url changed for security
    print(url)
    myFile = open(<datafile>, 'rb')    # This is the line i'm having issues with
    files = {'file': myFile}
    #print(files)
    r = requests.post(url, file=files)
except:
    print('Error')

any help would be greatly appreciated
Many Thanks

It should, if your code contains this row:

url = http:\\11.11.11.11     # invalid syntax, must be string

sorry, my bad, it is a string in the code, I just changed the address and forgot to put "" around it

Don't use general except clause that will mask what the error is. Remove the try/except to get exception description

After taking away the try/except I found out why it wasn't liking it. The path was not recognized.
I retyped the path and it worked, only problem is that after double checking the previous path was actually correct with no errors but for some reason retyping it worked.
Confused yes, but it's working :)