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Full Version: Delete a whole row if all cells contain certain values
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Hello !

I try to delete all rows from a Excel sheet, who satisfied this condition: all cells from a row must contain only the values "-" or "".

I use Python and openpyxl .

But my code, don't work well:

import openpyxl

wb1 = openpyxl.load_workbook(filename="testat_openpyxl.xlsx")

instr=""
for i in range(5, wb1["Centralizator"].max_row):

  for j in range(7,49):


    celval=wb1["Centralizator"].cell(row=i,column=j).value
    ins='{}=="-" or {}=="" and '.format(celval)
    instr=instr + ins
 if  instr[:-3]:

    wb1["Centralizator"].delete_rows(i,1)


wb1.save('testat_openpyxl.xlsx')
My idea is to create a big "if" statement , to check all cells from a row:

if wb1["Centralizator"].cell(row=5,column=7).value=="-" or 
wb1["Centralizator"].cell(row=5,column=7).value=="" and
wb1["Centralizator"].cell(row=5,column=8).value=="-" or
wb1["Centralizator"].cell(row=5,column=8).value==""
wb1["Centralizator"].cell(row=5,column=9).value=="-" or
wb1["Centralizator"].cell(row=5,column=9).value==""
.........loop until column 48............
wb1["Centralizator"].cell(row=5,column=48).value=="-" or
wb1["Centralizator"].cell(row=5,column=48).value==""
now jump to next row
if wb1["Centralizator"].cell(row=6,column=7).value=="-" or 
wb1["Centralizator"].cell(row=6,column=7).value=="" and
wb1["Centralizator"].cell(row=6,column=8).value=="-" or
wb1["Centralizator"].cell(row=6,column=8).value==""
.........loop until column 48...........
wb1["Centralizator"].cell(row=6,column=48).value=="-" or
wb1["Centralizator"].cell(row=6,column=48).value==""
next row.......until max_row....
you need to check/delete rows starting from last row and going up (or down - depending on how you look at it) to 1st