Python Forum

Suppose I see a line of code like

elif m.group('status').lower() in ['stopped', 'failed']:

And I want to see all statuses that are available.
I tried

logging.warning('m.groups = ' + ' '.join(str(m.group)))

But I get

Output:
TypeError: type object argument after * must be an iterable, not builtin_function_or_method

I have tried several methods, but I always get either the error message above or

Output:
m.groups = < b u i l t - i n   m e t h o d   g r o u p   o f   r e . M a t c h   o b j e c t   a t   0 x 7 f b 2 7 0 a 4 7 1 8 8 >

which is not what I'm looking for.

Is there a way of printing out all of the groups in the above scenario?

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I now think that it is not possible, because groups is a method that searches for a regex, rather than being a list.

Are you using regular expressions here? Please take a moment to re-read your post and consider what context you should be providing that currently isn't here.

You're joining the representation of a method, because you're not calling it.
Instead of calling group(number), you should call groups() on the match.
This will return the results of all groups in a tuple.