Python Forum

Hi,

can anyone please help me to write code for this one

5 5 5 5 5
5 4 4 4 4
5 4 3 3 3
5 4 3 2 2
5 4 3 2 1

kindly help, matrix value changes with Value of N
if n is 6 then

6 6 6 6 6 6
6 5 5 5 5 5
6 5 4 4 4 4
6 5 4 3 3 3
6 5 4 3 2 2
6 5 4 3 2 1

kindly help

We won't do your homework for you, but are happy to help. What have you written so far? Please post your effort.

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(Jun-09-2020, 12:57 PM)jefsummers Wrote: [ -> ]We won't do your homework for you, but are happy to help. What have you written so far? Please post your effort.

Hi,

i have tried and its not that much good code since i have started to learn python
and my code works only when n = 4

please guide me to refine so that i can take one variable an keep reducing that and print

n = int(input("value of n:"))
for i in range(n):
    print((n), end= ' ')
print()
print(n, end =' ')
for i in range(n-1):
    print((n-1), end= ' ')
print()
print((n),end = ' ')
print((n-1), end = ' ')
for i in range(n-2):
    print((n-2), end= ' ')
print()
print(n, end = ' ')
print(n-1, end = ' ')
print(n-2, end = ' ')
print(n-3, end =' ')

thank you

---

Hi,
This is the program which i written and i want to use loop with in the loop i keeps reducing like

and out put is

value of n:4

Output:
4 4 4 4 
4 3 3 3 
4 3 2 2 
4 3 2 1 

and when is n is greater 4 output will be like

value of n:5

Output:
5 5 5 5 5 
5 4 4 4 4 
5 4 3 3 3 
5 4 3 2 2
5 4 3 2 1

kindly help me to write loop

Thank you

To get you started -
The for statement in line 2 goes from 0 to one less than n (see how to use range in the docs). Better would be for i in range(n,0,-1):

You then don't want to print n in each column each row. Rather, if we count the columns and rows starting with 0 (typical Python), you want to subtract the row value from each column starting with the column value

Easiest way I can see is to create a list of n values of n. Print that. Next use that list and subtract 1 from every element starting with element 1. Print that. Next use the same list and subtract 1 from every element starting with element 2. And so on.

Hi,

Thank you jef, i got my code working in early morning 2 AM
Thank you for help and support
code:

n = int(input("value of n:"))
for i in range(n, 0,-1):#5, 4, 3, 2,1
for j in range(n,0,-1): #5, 4, 3, 2, 1
if j <= i:
print(i, end=' ')
else:
print(j, end=' ')
print()

Thanks and Regards
Vij

Hi,
Found this exercise amusing.
The post above (jefsummers) suggests numbers in lists, an exercise in indexing.
You may also try string slicing, possibly a bit easier, if your number < 10 :-)
Without comprehensions, the number of codelines for the list solution would be 8 and the slicing solution 6.
So way less than what you proposed originally.
I do believe that this is some solid beginner's exercise :-)
Paul

---

n = int(input("value of n:"))
for i in range(n, 0,-1):#5, 4, 3, 2,1
    for j in range(n,0,-1): #5, 4, 3, 2, 1
        if j <= i:
            print(i, end=' ')
        else:
            print(j, end=' ')
    print()

You actually found a third solution
Paul

Ahah. You wanted to find someone who will solve this problem for you? It can take enough time and I think that no one will do this for free) Only suggestions. Maybe you can find some help **removed**. Some of these websites can provide you with additional programming help.

@alfredharper, no one does a student's work, we only help them by showing clues/hints etc.