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Full Version: Name Error: name 'Stockton' is not defined
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data = DataPortal(model=m)
    
data.load(filename="Dataframe2.xlsx", range='D2:D6', set='I')
data.load(filename="Dataframe2.xlsx", range='A2:A99', set='J')
data.load(filename="Dataframe2.xlsx", range='A1:B99', param='d', index='J')
data.load(filename="Dataframe2.xlsx", range='G1:L99', param='c', format='transposed_array')
data.load(filename="Dataframe2.xlsx", range='D1:E6' , param='b', index='I')
data.load(filename="Dataframe2.xlsx", range='N1:O6' , param='i', index='I')

data = {None: {
    'e' : {Stockton:325000, Rockwall:50000, Joliet:350000, Atlanta:450000, York:170000},
}}

m = m.create_instance(data)
m = m.create_instance(data)
After running it there is the following error code:

Quote:NameError Traceback (most recent call last)
<ipython-input-264-1e6fce871313> in <module>
9
10 data = {None: {
---> 11 'e' : {Stockton:325000, Rockwall:50000, Joliet:350000, Atlanta:450000, York:170000},
12 }}
13

NameError: name 'Stockton' is not defined

The numbers are maximum restrictions and the city names are places. If somebudy could help or give any advice I'd be grateful.
As the error is saying 'Stockton' is not defined anywhere in the code shown neither is Rockwall, Joliet, Atlanta or York.
Did you mean for them to string values? add quotes to them.
data = {None: {
    'e': {'Stockton': 325000, 'Rockwall': 50000, 'Joliet': 350000,
          'Atlanta': 450000, 'York': 170000}}}
Thanks, I added the marks.

However this won't solve the problem you said before that the city names are not defined, right?
Could you tell me how I should to this?
It does solve the problem of NameError: name 'Stockton' is not defined
what do you want the key names to be represented as?
Note
https://docs.python.org/3/tutorial/datas...ctionaries Wrote:dictionaries are indexed by keys, which can be any immutable type; strings and numbers can always be keys. Tuples can be used as keys if they contain only strings, numbers, or tuples; if a tuple contains any mutable object either directly or indirectly, it cannot be used as a key. You can’t use lists as keys, since lists can be modified in place using index assignments, slice assignments, or methods like append() and extend().