Python Forum

I wrote this and since it creates an empty file it give me an error.

with open("food.json", "r+") as file:
    food = json.load(file)

Error:
Traceback (most recent call last):
  File "c:/Users/User/MyStuff/mltipls.py", line 4, in <module>
    food = json.load(file)
  File "C:\Users\User\AppData\Local\Programs\Python\Python38-32\lib\json\__init__.py", line 293, in load
    return loads(fp.read(),
  File "C:\Users\User\AppData\Local\Programs\Python\Python38-32\lib\json\__init__.py", line 357, in loads
    return _default_decoder.decode(s)
  File "C:\Users\User\AppData\Local\Programs\Python\Python38-32\lib\json\decoder.py", line 337, in decode
    obj, end = self.raw_decode(s, idx=_w(s, 0).end())
  File "C:\Users\User\AppData\Local\Programs\Python\Python38-32\lib\json\decoder.py", line 355, in raw_decode
    raise JSONDecodeError("Expecting value", s, err.value) from None
json.decoder.JSONDecodeError: Expecting value: line 1 column 1 (char 0)

I fixed it with:

with open("food.json", "r+") as file:
    try:
        food = json.load(file)
    except:
        food = {}
        json.dump(food, file)

I know empty except statements aren't advisable but I don't know what exception to use.
I tried:
except None
except json.decoder.JSONDecodeError
except JSONDecodeError
These all get their own errors.

(Jun-17-2020, 09:50 AM)mcmxl22 Wrote: [ -> ]I wrote this and since it creates an empty file it give me an error.

if the file does not exists, it will not create an empty file, but will raise FileNotFoundError.

If the file exists, but is empty or otherwise not valid JSON

import json
with open("food.json", "r+") as file:
    try:
        food = json.load(file)
    except json.decoder.JSONDecodeError:
        print('this is error')