Python Forum - A beginner code...

Hi everyone, first and foremost I am a completely beginner in coding, I am starting from scratch on my own. Is hard but I know that I can learn this because I love fix problems. Ok, here is my beginner issue:
This is a bar
People < 18 don´t pass
People >= 18 are allowed IF their name is not "Marco"
Hence, IF your name is Marco, Go home. IF your name is not Marco, Welcome.
So far I have this:

current_age = int(input("Your current age: "))
name = ""
if current_age <18:
    print ("Sorry, bye")
if current_age >= 18: 
    input ("and your name?: ")
    if name == "Marco":
        print ("Go home")
    else:
        print ("Welcome")

It discriminate by age, but not by name. Everyone is passing. I have burnt my brain for two days and I give up. Please help me

on line #6 you want to assign value returned from input() to name
And you don't need line#2

Hi, buran. So

current_age = int(input("Your current age: "))

if current_age <18:
    print ("Sorry, bye")
if current_age >= 18: 
    input ("and your name?: ")
    if name == "Marco":
        print ("Go home")
    else:
        print ("Welcome")

I have erased line 2. How Can I assign value returned from input() to name?

(Jun-18-2020, 05:06 AM)TheDude Wrote: [ -> ]How Can I assign value returned from input() to name?

the same way you assign the value for current_age :-)

current_age = int(input("Your current age: "))
 
if current_age < 18:
    print("Sorry, bye")
if current_age >= 18: 
    name = input("and your name?: ")
    if name == "Marco":
        print("Go home")
    else:
        print("Welcome")

current_age = int(input("Your current age: "))
name=input("and your name?: ")
if current_age <18:
    print ("Sorry, bye")
if current_age >= 18: 
    input ("and your name?: ")
    if name == "Marco":
        print ("Go home")
    else:
        print ("Welcome")

but now it doesn´t discriminate by age :( and also ask the name twice

You are asking for name input in two places now, one is in the correct location the other is actually assigning a value.
carefully look through each stage of what your code is now doing.

(Jun-18-2020, 05:13 AM)TheDude Wrote: [ -> ]but now it doesn´t discriminate by age

That's not true - it just ask for name, before check the age, but if the age is less than 18 it ill print sorry, buy

(Jun-18-2020, 05:13 AM)TheDude Wrote: [ -> ]and also ask the name twice

because you keep line #6.

if you want to check age before asking for name just replace current line 6 with line 2, as I show in my previous post

Ok guys, I am closer now.

current_age = int(input("Your current age: "))
name=input("and your name?: ")
if current_age <18:
    print ("Sorry, bye")
if current_age >= 18: 
    name
    if name == "Marco":
        print ("Go home")
    else:
        print ("Welcome")

the only problem is when the user is under 18, it should be say "sorry,bye" at first, and not ask for the name. I know is in line 6 but can´t figure it out.

Ok, I get it!

current_age = int(input("Your current age: "))

if current_age <18:
    print ("Sorry, bye")
if current_age >= 18: 
    name=input("and your name?: ")
    if name == "Marco":
        print ("Go home")
    else:
        print ("Welcome")

Thanks for the patience and the guidance. All the time was in front of me. I know is not easy for people like me, but I am gonna keep trying. Thanks!!!