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Hello !

This is a clasical example of pyvisa program:

import pyvisa
rm = pyvisa.ResourceManager()
rm.list_resources()
('ASRL1::INSTR', 'ASRL2::INSTR', 'GPIB0::12::INSTR')
inst = rm.open_resource('GPIB0::12::INSTR')
print(inst.query("*IDN?"))

Now, the problem is if I have a text file with multiple names and address of various instruments, something like this:

keithley,GPIB0::12::INSTR
lakeshore,GPIB0::11::INSTR
etc

How can I make the program from above to work without to dynamically create the variable with the name and address of each instrument from the file text?

I want to avoid this type of variable declaration:

rm = visa.ResourceManager()
vars()["lakeshore"] = rm.open_resource('GPIB0::11::INSTR')

Is possible?
Thank you!

Use a dictionary

(Jun-20-2020, 12:44 PM)Yoriz Wrote: [ -> ]Use a dictionary

I know how to use a dictionary but in this case, I have no idea how to do it. Because once I create the name of the instrument, then I need to acces its properties like instr.write("command"), inst.read(), etc.

my_dict = {}
rm = visa.ResourceManager()
my_dict["lakeshore"] = rm.open_resource('GPIB0::11::INSTR')
my_dict["lakeshore"].write("command")

(Jun-20-2020, 12:47 PM)Yoriz Wrote: [ -> ]

my_dict = {}
rm = visa.ResourceManager()
my_dict["lakeshore"] = rm.open_resource('GPIB0::11::INSTR')

And in this case how acces its properties? Like:

lakeshore.write("*IDN?")
print(lakeshore.read())

Ok!
Thank you !!!!!!!!

I had edited my reply to include an example of accessing write in the time that you were adding a reply

Thank you a lot!

From the performance point of view which method is faster: dictionary or vars()[]....?

I test the speed:

import time
my = {}

start_time = time.time()
my["clock"] = time
print(my["clock"].localtime())
print("--- %s seconds ---" % (time.time() - start_time))

start_time = time.time()
vars()["clock"] = time
print(vars()["clock"].localtime())
print("--- %s seconds ---" % (time.time() - start_time))

Output:time.struct_time(tm_year=2020, tm_mon=6, tm_mday=20, tm_hour=17, tm_min=40, tm_sec=0, tm_wday=5, tm_yday=172, tm_isdst=1)
--- 0.02257513999938965 seconds ---
time.struct_time(tm_year=2020, tm_mon=6, tm_mday=20, tm_hour=17, tm_min=40, tm_sec=0, tm_wday=5, tm_yday=172, tm_isdst=1)
--- 0.0029897689819335938 seconds ---

So, the dictionary method is 10x slower than vars()[] method.

import time
my = {}
my["clock"] = time

def test1():
    my["clock"] = time
    my["clock"].localtime()

def test2():
    vars()["clock"] = time
    vars()["clock"].localtime()


if __name__ == '__main__':
    import timeit
    print(timeit.timeit("test1()", setup="from __main__ import test1"))
    print(timeit.timeit("test2()", setup="from __main__ import test2"))

Output:1.4009026
1.504943

Seriously

from timeit import timeit
import time


r = timeit("vars()['clock'] = time", "from __main__ import time")
print(r)

my = {}

r = timeit("my['clock'] = time", "from __main__ import time, my")

print(r)

Output:0.1516461489991343
0.022416326999518787

Dict is faster.

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