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Full Version: Hi, I need help with defining user's input and applying it to code.
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import sys
from cs50 import get_string
from cs50 import get_int
from py_thesaurus import Thesaurus


def main():
   if len(sys.argv) != 2:
       print("Usage:python final.py read [or] thes")
       sys.exit(1)
ui = string(sys.argv[1])

if ui == "read"
   T = get_string("Enter Text: ")
   DG = get_int("What grade do you need? ")
   length = len(T)
   letters = 0
   S = T.count('.') + T.count('!') + T.count('?')
   W = T.count(' ')
   for i in range(length):
       if (T[i].isalpha()):
           letters += 1
   L = letters / W * 100
   S = S / W * 100
   calculate = 0.0588 * L - 0.296 * S - 15.8
   indexi = round(calculate)
   if (indexi == DG):
       print("You're right on!")
   if (indexi < DG):
       print("You need more. :( Consider longer words, sentences and/or paragraphs")
   if (indexi > DG):
       print("You passed your grade. Congrats!")



if ui == "thes"
   input_word = get_string("Word-")
   synonym = (input_word.get_synonym) 
   synonym_verb = (input_word.get_synonym(pos='verb'))
   synonym_adj = (input_word.get_synonym(pos='adj'))
   definition = (input_word.get_definition())
   antonym = (input_word.get_antonym())

   i = 0
   while i < 1: 
       print(f{synonym})
       print(f{synonym_verb})
       print(f{synonym_adj})
       print(f{definition})
       print(f{antonym})
       i += 1


if __name__ == "__main__":
   main()
Error:
#but I always get this error message:  File "final.py", line 13    if ui == "read"                  ^ SyntaxError: invalid syntax
You're missing the colon at the end of line 13. By the way, is your indentation correct?
The error message you get indicates that you haven't added the colon : at the end of the if statement on line 13, which results in the display of the error message.