I want to create an if-condition, but I'm not sure how to do it... I would like, that if the else-condition is true, it prints my message. How can I do that?
That's my recent try:
y = 'lol'
if y == True:
print ('y ist wahr!')
elif y == False:
print ('y ist nicht wahr!')
else:
print ('y ist weder wahr noch nicht wahr')
if else == True:
print ('Ich habe es, denke ich, verstanden')And that's the error I get:
Error:
if else == True:
^
SyntaxError: invalid syntax
I'm a starter, so it's probably easy to solve for you professionals
something = False
else_true = False
if something:
print('something is True')
else:
print('something is False')
else_true = True
if else_true:
print('else_true is True')
It doesn't make sense for else to have a condition. Like in English, it means "in the other case". That's also why you can't have an else on its own.
(Aug-09-2020, 10:55 AM)ndc85430 Wrote: [ -> ]It doesn't make sense for else to have a condition. Like in English, it means "in the other case". That's also why you can't have an else on its own.
What do you mean with "you can't have an else on its own"? Could you explain that please?
As in, you can't write
else:
# something here
because again,
else means "in the other case", so it has to follow an
if or
elif.
Of course, an
if on its own makes sense. You might want to do something when the condition is
True, but nothing if it is
False.
