Python Forum

I need an error message to display to the user if they try to enter a score over 100 and I need to use the sys.exit() to exit the program gracefully if any errors are detected. I need to do this in an if statement. I can't figure this out, I'm a total noob. Help please..

name = input("Please enter your First and Last Name: ")
score = int(input("Enter your first exam score: "))
score2 = int(input("Enter your second exam score: "))
score3 = int(input("Enter your third exam score: "))

average = (score + score2 + score3) // 3

if average >= 100:
    print("Error")
    sys.exit()
elif average >= 90 and average <= 100:
    print("You received an A.")
elif average >= 80 and average < 90:
    print("You received a B.")
elif average >= 70 and average < 80:
    print("You received a C.")
elif average >= 60 and average < 70:
    print("You received a D.")
else:
    print("You received an F.")
        
print("Report Card")
print("Name:", name)
print("You scored a", score, "on your first exam.")
print("You scored a", score2, "on your second exam.")
print("You scored a", score3, "on your third exam.")
print("Your average score is" ,average,"percent.")

What's wrong with what you have? (Other than probably wanting > 100 instead of >= 100.)

You could put in if statement after every variable that will ask for same input IF input does not meet the criteria, in this case its a number being over 100.

score = int(input("Enter your first exam score: "))
if score > 100:
   print("score can not be over 100!")
   score = int(input("Enter your first exam score: "))

score2 = int(input("Enter your second exam score: "))
if score2 > 100:
   print("score can not be over 100!")
   score2 = int(input("Enter your second exam score: "))

score3 = int(input("Enter your third exam score: "))
if score3 > 100:
   print("score can not be over 100!")
   score3 = int(input("Enter your third exam score: "))

if average >= 100: this means if average is HIGHER THAN or EQUALS TO 100
What you should use here is just > instead of >=