i know there is not a goto or similar command in python,im trying to make a menu with submenus
a main menu that gives you games/math/managment options,and when you choose one of them it brings you to another menu where you can run a task
however i want there to be a option in the submenus that allows you to go back to main menu ,and/or after the task is finished for it to go back to its mother submenu
here is the basic code
#!/usr/bin/python
print ("\n" * 200)
print ("Welcome,what would you like to do?type the number")
print ("\n")
print ("[1]:Math solver")
print ("[2]:exit")
print ("\n")
menu = input(": ")
if menu = 1
print ("\n" * 200)
print ("What type is your question?")
print ("\n" * 3)
print ("[1]:Bisquared-equasion")
print ("[2]:Exit")
print ("\n")
menu = input(": ")
if menu = 1if menu = 1 should run a task after which it should go back to the Math solver menu instead of quiting
how do i do that,im Really new so i need guidance and examples :(
Well, generally this would all be in a loop that would go until you got a 2 (exit). Then you could have a sub-loop for sub-menus.
I would suggest having each menu loop in it's own function, that returns when the loop is over. Then you would have something like:
if menu == 1:
math_menu()It help organize your code.
(Apr-24-2017, 04:48 PM)ichabod801 Wrote: [ -> ]Well, generally this would all be in a loop that would go until you got a 2 (exit). Then you could have a sub-loop for sub-menus.
I would suggest having each menu loop in it's own function, that returns when the loop is over. Then you would have something like:
if menu == 1:
math_menu()
It help organize your code.
how will that look in my code,i have just started learning and can't get where/how to use the "math_menu()" part
i just need to see it in my code as i know what does what there,i tried reading that thread but i don't understand how to apply that to my script,thanks in advance ,and sorry for being inexperienced and dumb.not good at understanding others code
#!/usr/bin/python
def math_menu():
while True:
print ("\n" * 200)
print ("What type is your question?")
print ("\n" * 3)
print ("[1]:Bisquared-equasion")
print ("[2]:Exit")
print ("\n")
menu = int(input(": "))
if menu == 1:
bisquared()
elif menu == 2:
break
while True:
print ("\n" * 200)
print ("Welcome,what would you like to do?type the number")
print ("\n")
print ("[1]:Math solver")
print ("[2]:exit")
print ("\n")
menu = int(input(": "))
if menu == 1:
math_menu()
elif menu == 2:
break
If change my code a little in link that metulburr post.
You see that it fit this kind of task well.
def solve():
answer = int(input('What is 2 + 2? '))
if answer == 4:
print('\nCorrect')
else:
print('\nWrong')
input('Push enter to retun to menu')
def menu():
while True:
print('(1) Solve something')
print('(Q) Quit')
choice = input('Enter your choice: ').lower()
if choice == '1':
solve()
elif choice == 'q':
return
else:
print('Not a correct choice: <{}>,try again'.format(choice))
if __name__ == '__main__':
menu()
Certainly its me again and im EXTREMELY sorry for bothering so much but it gives me this error
Error:
File "foxware 2.0.py", line 3
def math_menu()
^
SyntaxError: invalid syntax
am i supposed to paste the whole code in the brackets() or have i done something wrong elsewhere
this time im posting my whole code incase its because of a mistake elsewhere
#!/usr/bin/python
def math_menu()
while True:
print ("\n" * 200)
print ("Welcome,what would you like to do?type the number")
print ("\n")
print ("[1]:Math solver")
print ("[2]:exit")
print ("\n")
menu = input(": ")
if menu == 1
print ("\n" * 200)
print ("What type is your question?")
print ("\n" * 3)
print ("[1]:Bisquared-equasion")
print ("[2]:Exit")
print ("\n")
menu = int(input(": "))
if menu == 1
bisquared()
import math
print ("Ax*2+Bx+C=0")
print ("what is your A?")
(a) = input('my a is: ')
print ("what is your B?")
(b) = input('my b is: ')
print ("what is your C?")
(c) = input('my c is: ')
print ("calculating")
a = float(a)
b = float(b)
c = float(c)
b2 = b*b
b2 = float(b2)
d = b2-4*a*c
d = float(d)
if d < 0:
d = str(d)
print ("\n" * 200)
print (" D is Less than 0,There are no answers")
d = str(d)
exit
d = float(d)
if d >= 0:
d = str(d)
print ("D is: " + d )
d = float(d)
sqd = math.sqrt(d)
sqd = float(sqd)
x1a = -b+sqd
x1a = float(x1a)
x2a = -b-sqd
x2a = float(x2a)
ax2 = a*2
ax2 = float(ax2)
x1 = x1a/ax2
x1 = str(x1)
x2 = x2a/ax2
x2 = str(x2)
if d >= 0:
d = str(d)
print ("\n" * 200)
print ("your X1 is " + x1 + " your X2 is " + x2)
print ("your discriminant is " + d )
exit
elif menu == 2
break
if menu = 2
exitim really sorry again.
You missed the colon at the end of the line.