Python Forum

I try to find all characters from the given list and replace them with one character. I`m getting "object has no attribute 'replaceall' ?

list = 'bcdfghjklmnpqrstuvwxyzBCDFGHJKLMNPQRSTUVWXYZ'
string = "aabbccddeeff"
string2 = string.replaceall(list, "!")
print(string2)

I would like to get: !!bbccdd!!ff as a and e are not on the list.

There is no "str.replaceall()". There is a "str.replace()" method, but it doesn't do what you want to do.

Output:>>> help(str.replace)
Help on method_descriptor:

replace(self, old, new, count=-1, /)
    Return a copy with all occurrences of substring old replaced by new.
    
      count
        Maximum number of occurrences to replace.
        -1 (the default value) means replace all occurrences.
    
    If the optional argument count is given, only the first count occurrences are
    replaced.

There is the re (regular expressions) library. It has a function named "sub()" that looks like it will do what you want.

https://docs.python.org/3/library/re.html

Search for "complementing" in the section about Regular Expression Syntax..

You can do

from string import ascii_letters
spam =  'bcdfghjklmnpqrstuvwxyzBCDFGHJKLMNPQRSTUVWXYZ'

trans = str.maketrans({char:'!' for char in ascii_letters if char not in spam})
eggs = "aabbccddeeff"
foo = eggs.translate(trans)
print(foo)

Docs on str.maketrans() and str.translate()

peterp

deanhystad

buran