Python Forum

My goal is to write a function that takes a letter as an argument, it loops through its words and gives me False if it contains 'e' otherwise it is True.
The correct code is:

def has_no_e(letter):
    for i in letter:
        if i=='e':
            return False
        
    return True

But I tried with one another attempt:

def has_no_e2(letter):
    for i in letter:
        if i!='e':
            return True
        
    return False

But this code does not give me the correct answer if I try for example

print(has_no_e2('Robert'))

What is wrong?!

for char in "Robert":
    print(char)

Output:R
o
b
e
r
t

The first element is the str R. What do you think will happen, if you return True?

(Dec-14-2020, 10:21 AM)DeaD_EyE Wrote: [ -> ]
for char in "Robert":
    print(char)
Output:R
o
b
e
r
t
I thought it would loop through all the words in there.
The first element is the str R. What do you think will happen, if you return True?

(Dec-14-2020, 10:21 AM)DeaD_EyE Wrote: [ -> ]
for char in "Robert":
    print(char)
Output:R
o
b
e
r
t
The first element is the str R. What do you think will happen, if you return True?

f
Allright ! I've got it now! I missunderstood the Boolean! True or False will terminate the whole loop

(Dec-14-2020, 11:43 AM)pooyan89 Wrote: [ -> ]True or False will terminate the whole loo

No, not the True or False, but the return statement.

def function():
    for _ in range(10):
        return # <-- function will return None
               # the loop does not continue if you return from a function
               # in this case the first iteration will return None
               # the None is implicit

It's not the True or False, the return statement is what will return something.

A plain return returns None.
A return in a for-loop will imminently return and the for-loop won't do further iterations.

pooyan89

DeaD_EyE

pooyan89

pooyan89

buran

DeaD_EyE