Python Forum

my code:

largest = None
smallest = None
while True:
    num = input("Enter a number: ")
    if num == "done" : 
        break
    try:
        num1 = int(num)
    except ValueError:
        print('Invalid input')
        continue
for number1 in num:
    if largest is None:
        largest = number1
    elif largest > number1:
        largest = number1
print("Maximum is", largest)
for number2 in num:
    if smallest is None:
        smallest = number2
    elif smallest < number2:
        smallest = number2
print("Minimum is", smallest)

My desired output would be if I used 2,8,9,python,4,10 would be:

Invalid input
Maximum is 10
Minimum is 2

But my output shows:

Invalid input
Maximum is d ← Mismatch
Minimum is o ← Mismatch

d and o are from word done

You are using num for the input, then expect that num will end up being the list that you can cycle over, and you also never append the integer to the list.
Minor changes, try:

largest = None
smallest = None
num = []
while True:
    num_input = input("Enter a number: ")
    if num_input == "done" : 
        break
    try:
        num1 = int(num_input)
        num.append(num1)
    except ValueError:
        print('Invalid input')
        continue
for number1 in num:
    if largest is None:
        largest = number1
    elif largest > number1:
        largest = number1
print("Maximum is", largest)
for number2 in num:
    if smallest is None:
        smallest = number2
    elif smallest < number2:
        smallest = number2
print("Minimum is", smallest)

Output:
Enter a number: 2
Enter a number: 8
Enter a number: 9
Enter a number: python
Invalid input
Enter a number: 4
Enter a number: 10
Enter a number: done
Maximum is 2
Minimum is 10

Oh, and btw - you reverse minimum and maximum as shown in results above.

Hint: Use a function to split user-input and logic to get minimum and maximum.

def get_number():
    """
    Helper function to get one int from user input
    """
    while True:
        num_input = input("Enter a number: ")
        if num_input.lower() == "done": 
            return None
        try:
            return int(num_input)
        except ValueError:
            print('Invalid input')


def get_min_max():
    """
    Primitive implementation using a list with min and max.
    """
    numbers = []
    while True:
        number = get_number()
        if number is None:
            break
        numbers.append(number)
    return min(numbers), max(numbers)


def get_min_max_oneshoot():
    """
    Returns minimum and maximum of entered ints.
    The ints itself are not stored in a list.
    """
    first_run = True
    minimum = None
    maximum = None
    while True:
        number = get_number()
        if number is None:
            break
        if first_run:
            first_run = False
            minimum = number
            maximum = number
            continue
        minimum = min(number, minimum)
        maximum = max(number, maximum)
    return minimum, maximum


min_value_1, max_value_1 = get_min_max_oneshoot()
# min_value_2, max_value_2 = get_min_max()

The function get_min_max is the easier implementation.
get_min_max_oneshoot is like your implementation, but without storing any history values.
You get only min and max, all other values are not stored.

(Dec-21-2020, 01:09 PM)jefsummers Wrote: [ -> ]Oh, and btw - you reverse minimum and maximum as shown in results above.

Thank you for your help, my head almost exploded from this one.

(Dec-21-2020, 01:51 PM)DeaD_EyE Wrote: [ -> ]Hint: Use a function to split user-input and logic to get minimum and maximum.

def get_number():
    """
    Helper function to get one int from user input
    """
    while True:
        num_input = input("Enter a number: ")
        if num_input.lower() == "done": 
            return None
        try:
            return int(num_input)
        except ValueError:
            print('Invalid input')


def get_min_max():
    """
    Primitive implementation using a list with min and max.
    """
    numbers = []
    while True:
        number = get_number()
        if number is None:
            break
        numbers.append(number)
    return min(numbers), max(numbers)


def get_min_max_oneshoot():
    """
    Returns minimum and maximum of entered ints.
    The ints itself are not stored in a list.
    """
    first_run = True
    minimum = None
    maximum = None
    while True:
        number = get_number()
        if number is None:
            break
        if first_run:
            first_run = False
            minimum = number
            maximum = number
            continue
        minimum = min(number, minimum)
        maximum = max(number, maximum)
    return minimum, maximum


min_value_1, max_value_1 = get_min_max_oneshoot()
# min_value_2, max_value_2 = get_min_max()

The function get_min_max is the easier implementation.
get_min_max_oneshoot is like your implementation, but without storing any history values.
You get only min and max, all other values are not stored.

Thank you for the help, I appreciate it.