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I got code via link in a post at stackoverflow, but unable to understand how in the code there is a fixed value taken as input, while the code asks none.

Code is at: https://ideone.com/nj4CF as given in the answer at the link on (https://stackoverflow.com/a/10907207/3693431
).

Here, fixed value of 6 is taken up.
I tried to look and found that ideone takes prog (program name: prog.py) as single parameter each time. But that means there should be 4 characters not 6. So, is the parameter stored as 'prog' and not prog.

There is nothing strange here. Suppose that you write in C

int n;
scanf("%d", &n);

this code doesn't ask anything but it reads an integer in standard input. So does the C++ code

int n;
cin >> n;

or the Python 3 code

n = int(input())

Gribouillis: sorry that just changed text while you answered.

(Jan-28-2021, 03:22 PM)jahuja73 Wrote: [ -> ]Gribouillis: sorry that just changed text while you answered. To provide link to the Cpp code, it is at :

https://ideone.com/OR4VZ.

I concur with your answer for the cpp code. Please answer the changed post for python code.

(Jan-28-2021, 11:35 AM)jahuja73 Wrote: [ -> ]Here, fixed value of 6 is taken up.
I tried to look and found that ideone takes prog (program name: prog.py) as single parameter each time. But that means there should be 4 characters not 6. So, is the parameter stored as 'prog' and not prog.

The code is meant to be run from command line and not as a script.
Then 6 is given as argument from command line.

C:\Python27
λ python prog.py 6

Output:6
5 1
4 2
4 1 1
3 3
3 2 1
3 1 2
.....

As of 2020 is Python 2.7 officially dead💀

jahuja73

Gribouillis

jahuja73

jahuja73

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