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if (str(k)) in numer:
print ('JÁ EXISTE')
goto to de line that begininig de boddy of program.
the number existe so, dont wrirte and must go to random
i am 72 years old i beginning in basic business in Nixdorf computer.
i am portuguese and dont write correctly de english
thanks

Esteja ciente de que você pode usar o Google Translate para traduzir do português para o inglês. Isso faz um bom trabalho e ajudará com suas postagens.
Quanto a esta postagem, qual é o valor de k?
a instrução que você mostra, está testando para ver se k, convertido em string está contido em numer, então imprima 'JÁ EXISTE'

Google Translate: https://translate.google.com/

(Feb-01-2021, 09:49 PM)jmabrito Wrote: [ -> ] if (str(k)) in numer:
print ('JÁ EXISTE')
goto to de line that begininig de boddy of program.
the number existe so, dont wrirte and must go to random
i am 72 years old i beginning in basic business in Nixdorf computer.
i am portuguese and dont write correctly de english
thanks

the variable k comes from a random compare with a txt that has inserted 2 4 9 12 8 3 and if ok is different from any of these numbers it writes, if it should not go to random.The error is that it is always recording whether it already exists or not.

import random
for r in range(15):
    for i in range(1):    # se estivesse 5 mostrava 5 numeros      
      #print(random.randint(1 ,25))
      k=random.randint(1, 16)
      print (k)
    arq = "bjjj.txt"
    with open(arq ,'r+') as arquivo:
     numer = arquivo.readline()
    if not(str(k)) in numer:
                print ('não EXISTE')
    file1 = open('bjjj.txt', 'a+')
    file1.seek(0)
    file1.write(' ' + str(k))
    file1.close()
   
    if (str(k)) in numer:
                print (' EXISTE')
    print(k)
    print(numer, end='')

the variable k comes from a random compare with a txt that has inserted 2 4 9 12 8 3 and if is different from any of these numbers it writes, if it should not, go to random.The error is that it is always recording whether it already exists or not.

The problem why it always "thinks" number is not in the file, because when you read from file line has new-line char at the end '\n'. so it is never equal.
That said,there is a lot of redundant code in your snippet

the file

Output:2
4
9
12
8
3

import random
fname = "bjjj.txt"
with open(fname) as f:
    numbers = [int(line) for line in f]
# print the numbers in the file:
print(numbers)

with open(fname, 'a') as f: # open file in append mode
    for r in range(15): # loop 15 times
        k=random.randint(1, 16)
        if k not in numbers:
            print (f'{k} não EXISTE')
            numbers.append(k)
            f.write(f'{k}\n')
        else:
            print (f'{k} EXISTE')

Reading your question a second time, I see that most likely I was wrong as to how the file looks like
I see that in your file numbers are on the same line.
In this case the problem is if not(str(k)) in numer:`

here not(str(k)) is False always. And you condition is actually if False in numer: - which is always evaluated False

Note that you approach is prone to errors e.g. you have 12 in your file. the way you check, even if you fix the condition, will eleminate also 1 and 2 (although 2 is present also separately).

>>> '1' in '2 4 9 12 8 3\n'
True

file:

Output:
2 4 9 12 8 3

import random
fname = "bjjj.txt"
with open(fname) as f:
    numbers = f.readline().strip().split()
# print the numbers in the file:
print(numbers)
for _ in range(15): # loop 15 times
    k = str(random.randint(1, 16))
    if k not in numbers:
        print (f'{k} não EXISTE')
        numbers.append(k)
    else:
        print (f'{k} EXISTE')
with open(fname, 'w') as f: # open file in write mode
    f.write(f'{" ".join(numbers)}\n')

(Feb-02-2021, 01:11 PM)jmabrito Wrote: [ -> ]
import random
for r in range(15):
    for i in range(1):    # se estivesse 5 mostrava 5 numeros      
      #print(random.randint(1 ,25))
      k=random.randint(1, 16)
      print (k)
    arq = "bjjj.txt"
    with open(arq ,'r+') as arquivo:
     numer = arquivo.readline()
    if not(str(k)) in numer:
                print ('não EXISTE')
    file1 = open('bjjj.txt', 'a+')
    file1.seek(0)
    file1.write(' ' + str(k))
    file1.close()
   
    if (str(k)) in numer:
                print (' EXISTE')
    print(k)
    print(numer, end='')
the variable k comes from a random compare with a txt that has inserted 2 4 9 12 8 3 and if is different from any of these numbers it writes, if it should not, go to random.The error is that it is always recording whether it already exists or not.

i run your program and
Traceback (most recent call last):
File "C:\Users\José Brito\AppData\Local\Programs\Python\Python39\teste3.py", line 4, in <module>
numbers = [int(line) for line in f]
File "C:\Users\José Brito\AppData\Local\Programs\Python\Python39\teste3.py", line 4, in <listcomp>
numbers = [int(line) for line in f]
ValueError: invalid literal for int() with base 10: '2 3 4 5 6 7 8 9 11 6'
>>>

(Feb-02-2021, 01:43 PM)buran Wrote: [ -> ]Reading your question a second time, I see that most likely I was wrong as to how the file looks like
I see that in your file numbers are on the same line.
In this case the problem is if not(str(k)) in numer:`

here not(str(k)) is False always. And you condition is actually if False in numer: - which is always evaluated False

Note that you approach is prone to errors e.g. you have 12 in your file. the way you check, even if you fix the condition, will eleminate also 1 and 2 (although 2 is present also separately).
>>> '1' in '2 4 9 12 8 3\n'
True
file:
Output:
2 4 9 12 8 3
import random
fname = "bjjj.txt"
with open(fname) as f:
    numbers = f.readline().strip().split()
# print the numbers in the file:
print(numbers)
for _ in range(15): # loop 15 times
    k = str(random.randint(1, 16))
    if k not in numbers:
        print (f'{k} não EXISTE')
        numbers.append(k)
    else:
        print (f'{k} EXISTE')
with open(fname, 'w') as f: # open file in write mode
    f.write(f'{" ".join(numbers)}\n')

thanks work very well

Note, my first post assume each number is on separate line in the file (it is mentioned in the post)
Then, on second reading I thought you may have only one line, so look at the snippet in that post

There's a problem. Even if this number does exist, it continues to a voice that announces that number. pyttsx3
Thank you instruct me that, if "exists" you should go to the FOR, looking for another number. Thank you

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