Python Forum

Hi, i trying to figure out how the except work is...
in this python code

try:
    raise Exception("a", "b")
except Exception as e:
    print(e)
    print(e.__str__())
    print(e.args)

keyword

as e

in here mean the "e" will catch/cover the Exception class isn't it ? so does it mean the "e" variable will become an object like this ?

e = Exception("a", "b")

so how could the

print(e)
print(e.__str__())
print(e.args)

give an output

Output:
a
a
('a',)

respectively....doesnt mean if we try to

print(object)

will give us an sort of output like this

Output:
<__main__.e object at 0x0000016BF4C0F880>

When you print() an object, it will generally look for a __str__() method of that object. You should only get a print of the object's address for objects that don't have a __str__ method, or in its absence, a __repr__ method.

If you make your own class and don't provide either method, you'll get that odd default string.

Exception objects have a __str__ method, so that is what is printed. For them, it prints out the passed in information.

print() should only print things like this "<__main__.e object at 0x0000016BF4C0F880>" if the thing being printed does not have a more natural string representation. In Python everything is an object, even numbers. You would be very disappointed if this happened.

x = 3+5
print(x)

Output:
<int object at x0000016BF4C0F880>

If you write classes that have a reasonable string representation you should write dunder methods __str__ and/or __repr__ so you can get better information displayed from a print.