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> pipe(s) in = subprocess.Popen()
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pipe(s) in = subprocess.Popen()
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with proper formatting.
Skaperen
Feb-13-2021, 11:48 PM
invoking
subprocess.Popen(...,stdout=PIPE,stderr=PIPE)
returns 2 pipes or 1 pipe or is not valid?
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> pipe(s) in = subprocess.Popen()