Python Forum

Hey,
Can you please help me implement this program using python. Huh

I have a list:
The input

list=[["word1", "word2"],["word1", "word2","word1"], ["word4", "word5","word4", "word5", "word2", "word3"]]

The output:

Output:out=[
   {"word1", "word2",2}, {"word2", "word1",1},{"word4", "word5",2},{"word5", "word4",1},
{"word5", "word2",1},{"word2", "word3",1}

]

how it works:
it calculates the successive words in a sub-list, and it updates if it finds a new occurrence in a sub-list

I had a tough time with this because a list of sets reverses the order of combinations like

{word2, word1}

and makes them

{word1, word2}

. The best I can do is a list of lists.

word_list = [
	["word1", "word2"],
	["word1", "word2","word1"],
	["word4", "word5","word4", "word5", "word2", "word3"]]

out = []
count = []

for array in word_list :
	for marker in range (len (array)) :
		try :
			tester = [array [marker], array [marker + 1]]
			if tester in out :
				count [out.index (tester)] += 1
			else :
				count.append (1) 
				out.append (tester)
		except IndexError :
			pass

marker = 0
for array in out :
	array.append (count [marker])
	marker += 1
print (out)

Cheating with formatting. Sets are awkward to use in something like this. How do you get the count out of the set? A dictionary is a much better fit, and a counting dictionary does all the work. Just pretty up the output if required.

from collections import Counter

groups=[
    ["word1", "word2"],
    ["word1", "word2","word1"],
    ["word4", "word5","word4", "word5", "word2", "word3"]]

out = Counter([(a,b)  for group in groups for a, b in zip(group, group[1:])])
pairs = ', '.join(f'{{"{key[0]}", "{key[1]}", {value}}}' for key, value in out.items())
print(f'out = [{pairs}]')

Output:
out = [{"word1", "word2", 2}, {"word2", "word1", 1}, {"word4", "word5", 2}, {"word5", "word4", 1}, {"word5", "word2", 1}, {"word2", "word3", 1}]

(Feb-27-2021, 06:09 PM)deanhystad Wrote: [ -> ]Cheating with formatting. Sets are awkward to use in something like this. How do you get the count out of the set? A dictionary is a much better fit, and a counting dictionary does all the work. Just pretty up the output if required.
from collections import Counter

groups=[
    ["word1", "word2"],
    ["word1", "word2","word1"],
    ["word4", "word5","word4", "word5", "word2", "word3"]]

out = Counter([(a,b)  for group in groups for a, b in zip(group, group[1:])])
pairs = ', '.join(f'{{"{key[0]}", "{key[1]}", {value}}}' for key, value in out.items())
print(f'out = [{pairs}]')
Output:
out = [{"word1", "word2", 2}, {"word2", "word1", 1}, {"word4", "word5", 2}, {"word5", "word4", 1}, {"word5", "word2", 1}, {"word2", "word3", 1}]

Exactly what I want thanks

hamidze

BashBedlam

deanhystad

hamidze