Python Forum

I want to run this loop but it skips all the conditions and always runs n==1.
At the start of the code, I want it to run n==0 and get the data from the exchange. Then match with the order_id for data and set n==2 and count +1.

if data is not found I want it to run n == 1: code. Every time the count value is higher than loop_speed it must get new data from the exchange.
I know there is some problem with the loop help me solve it.

global data
global count
count = 0
global n
n = 1
loop_speed=10

def order_info(order_id):
  # print (loop_speed)
  # print (count)
   global count
   global n
   global data
   if count == 0:
        try:
            #order_id = 121553199503
            data = exchange.fetchOpenOrders(symbol)
            for d in data:
                if float(d['id']) == order_id:
                    info = d['info']
                    count = count + 1
                    print ("new")
                    print (info)
                    print (count)
                    n = 2
        except Exception as e:
            print (type(e).__name__, str(e))
            time.sleep(1)
   elif count <= loop_speed:

        # order_id = 121553198710
        #order_id = 121840387739
        print ('yess')
        for d in data:
            if float(d['id']) == order_id:
                info = d['info']
                print ("next")
                print (info)
                count = count + 1
                n = 2
                break
            else:
                n = 1
   elif count >= loop_speed:
        print (count)
        count = 0
        #order_id = 121840387739
        print ('y')
        for d in data:
            if float(d['id']) == order_id:
                info = d['info']
                print ("max")
                print (info)
                n = 2
                break
            else:
                n = 1
   elif n == 1:
        try:
            print ('true')
            info = exchange.fetchOrder(order_id)['info']
            count = count + 1
            print (info)
            print (count)
        except Exception as e:
            print (type(e).__name__, str(e))
            time.sleep(1)
            n == False
   return (info)

This will never run:

   elif n == 1:
        try:
            print ('true')
            info = exchange.fetchOrder(order_id)['info']
            count = count + 1
            print (info)
            print (count)
        except Exception as e:
            print (type(e).__name__, str(e))
            time.sleep(1)
            n == False

Because one of these will always be True:

   elif count <= loop_speed:
    ...
   elif count >= loop_speed:

You need to write a description of what you want to do with enough clarity and detail that somebody could convert the description to code. This is not adequate.

Quote:I want to run this loop but it skips all the conditions and always runs n==1.
At the start of the code, I want it to run n==0 and get the data from the exchange. Then match with the order_id for data and set n==2 and count +1.

if data is not found I want it to run n == 1: code. Every time the count value is higher than loop_speed it must get new data from the exchange.

(Feb-17-2022, 03:58 AM)deanhystad Wrote: [ -> ]This will never run:

   elif n == 1:
        try:
            print ('true')
            info = exchange.fetchOrder(order_id)['info']
            count = count + 1
            print (info)
            print (count)
        except Exception as e:
            print (type(e).__name__, str(e))
            time.sleep(1)
            n == False

Because one of these will always be True:

   elif count <= loop_speed:
    ...
   elif count >= loop_speed:

You need to write a description of what you want to do with enough clarity and detail that somebody could convert the description to code. This is not adequate.

Quote:I want to run this loop but it skips all the conditions and always runs n==1.
At the start of the code, I want it to run n==0 and get the data from the exchange. Then match with the order_id for data and set n==2 and count +1.

if data is not found I want it to run n == 1: code. Every time the count value is higher than loop_speed it must get new data from the exchange.

thanks, I have the problem it is going into the else loop and setting the value as one.

but I want to set n=1 only when the data value is not found

count = 0
loop_speed = 5
n=2
data = [1,2,3]
order_id = 3

if count == 0:
 for d in data:
   if float(d) == order_id:
     print ("count==0")
     print (count)
     count = count + 1
     print (count)
     info = d
     print (info)
elif count <= loop_speed and  n != 1:
  for d in data:
   if float(d) == order_id:
    print ("count <= loop_speed")
    print (count)
    count = count + 1
    print (count)
    info = d
    print (info)
    break
   else:
     n = 1
else:  
  for d in data:
   if float(d) == order_id:
    print ("else")
    print (count)
    count = 0 
    print (count)
    info = d
    print (info)
    break
  else:
     n = 1
if n == 1:
    print ("n==1")
    print (count)
    count = count + 1
    print (count)
    n = 2

What do you mean by "when the data value is not found"? Do you mean when float(d) == ordder_id for all values of d in data?

How about something like this:

count = data.count(str(order_id))
if count > 0:
    ...
else:
    ...

(Feb-17-2022, 06:06 AM)deanhystad Wrote: [ -> ]What do you mean by "when the data value is not found"? Do you mean when float(d) == ordder_id for all values of d in data?

How about something like this:

count = data.count(str(order_id))
if count > 0:
    ...
else:
    ...

No when data = exchange.fetchOpenOrders(symbol) which it got from the exchange does not match or is not found with the order id. It must set n = 1 or it must return the info.

if I put the code outside the function it works but when I put in the function it is just running. count = 0 one time then it sets n=1 and the other loops is skipped.

https://colab.research.google.com/drive/1PRwWv71-_WPMrKnO3zW_Ptk3xNoq8N8U?usp=sharing

In both examples shown here:
https://colab.research.google.com/drive/...sp=sharing

You did this:

if n == 1:

In the code you posted here you do this:

elif n == 1:

That is why the posted code never runs the n == 1 part.

I think there are a lot of problems with the code, but that is the one that is making it work differently than when it wasn't in a function. I think you should write a description of what the code does. Using the word "and" more than twice indicates the function is trying to do too many things and should be refactored. I see a "check_open_orders(symbol, order_id)" function that returns a list of orders with matching id's. Actually, that is all I see for functions, but I don't understand what the count and clock rate is doing.