Python Forum

i upgrade (Clean install) python from 3.9 to 3.10.5
and try this code

import subprocess
subprocess.call("title Test pause & Pause")

then it failed:

Error:
 Traceback (most recent call last):
 File "C:\Users\GIGABYTE\Desktop\test.py", line 2, in <module>
    subprocess.call("title Test pause & Pause")
  File "C:\Python\Python310\lib\subprocess.py", line 345, in call
    with Popen(*popenargs, **kwargs) as p:
  File "C:\Python\Python310\lib\subprocess.py", line 969, in __init__
    self._execute_child(args, executable, preexec_fn, close_fds,
  File "C:\Python\Python310\lib\subprocess.py", line 1438, in _execute_child
    hp, ht, pid, tid = _winapi.CreateProcess(executable, args,
FileNotFoundError: [WinError 2] The system cannot find the file specified

any clue to fix this?

Try this perhaps

subprocess.call("title Test pause & Pause", shell=True)

If it works, read a tutorial about the subprocess module.

(Jul-28-2022, 04:58 PM)Gribouillis Wrote: [ -> ]Try this perhaps

subprocess.call("title Test pause & Pause", shell=True)

If it works, read a tutorial about the subprocess module.

thank for the reply,
now the error does not appear,
and sadly the cmd window does not appear too

I don't know the Windows OS, but you could perhaps call the 'cmd' command to open a cmd window, for example

subrocess.call(['cmd', '/k', 'title spam'])

or something similar.

You should be using subprocess.run() instead of subprocess.call(). Subprocess.call() is the old Python 2.7 way of doing things.

Upgrading is not the source of your problem. I get the same error running with Python 3.9.

(Jul-28-2022, 05:23 PM)Gribouillis Wrote: [ -> ]I don't know the Windows OS, but you could perhaps call the 'cmd' command to open a cmd window, for example

subrocess.call(['cmd', '/k', 'title spam'])

or something similar.

thank you, this the solution, I will give you a point

import subprocess
subprocess.call(['cmd', '/k', 'title Test pause & Pause & exit'])

(Jul-28-2022, 05:26 PM)deanhystad Wrote: [ -> ]You should be using subprocess.run() instead of subprocess.call(). Subprocess.call() is the old Python 2.7 way of doing things.

Upgrading is not the source of your problem. I get the same error running with Python 3.9.

thank you, the call and run give same result as run, I will give you point too

import subprocess
subprocess.run(['cmd', '/k', 'title Test pause & Pause & exit'])