Hi.
How to convert in Python3 sets of unsigned integer 16 bits to ASCII equivalent like picture please ?
Input is a 16bit unsigned int witch represents two ASCII chars.
Result should be a string with inverted bytes (not 6A338F67, but A633F876).
Thanks,
Jozef
[attachment=2374]
Use int() to convert numeric strings to int objects.
print(int("0x3846", 16)) (str, base)Output:
14406
Python does not have 16 bit (or any fixed number of bits) ints, so signed/unsigned is not a thing in Python.
(May-19-2023, 11:03 AM)deanhystad Wrote: [ -> ]Use int() to convert numeric strings to int objects.
print(int("0x3846", 16)) (str, base)Output:
14406
Python does not 16 bit (or any fixed number of bits) ints, so signed/unsigned is not a thing in Python.
Thanks but my source is your result
Source: 13889
Result ASCII hex code: 6A = ASCII 6 as 0x36 and A as 0x41
The first step is convert 13889 to 0x3641 and then to ASCII string 6A and finally swap string result to A6
n=13889
print(bytes.fromhex(f'{n:02X}').decode())
print(bytes.fromhex(f'{n:02X}').decode()[::-1])Output:
6A
A6
Ok, I went the wrong direction.
13889 -> bytes = (0x36, 0x41) or (54, 65) -> ascii characters = ("6", "a") -> string = "6a"
number = 13889
as_bytes = number.to_bytes(2, "big")
as_ascii = "".join(chr(b) for b in as_bytes)
print(as_ascii)
Output:
6a
(May-19-2023, 11:28 AM)buran Wrote: [ -> ]n=13889
print(bytes.fromhex(f'{n:02X}').decode())
print(bytes.fromhex(f'{n:02X}').decode()[::-1])Output:
6A
A6
Thank you very much for rapid help, this is it !!!
Of course, decode(). So many nice tools in Python.
n = 13889
print(n.to_bytes(2, "big").decode())
print(n.to_bytes(2, "little").decode())
Output:
6A
A6