Python Forum

Hi everyone,

I would like to set the permission when using

from os import makedirs

I would like to have (for a directory) d-rwx-r-r (in other for "others") to be able to read the files inside that folder.

When I do a stat on a folder that have the permission that I want I get

Output:
(0755/drwxr-xr-x)

When I transpose this in python -->

makedirs('/somewhere', mode=0o0755)

The created folder give me another permission than expected..

Output:
(0750/drwxr-x---)

Any ideas ?

I try the same on my computer and it works

Output:
λ python
Python 3.10.6 (main, May 29 2023, 11:10:38) [GCC 11.3.0] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> from os import makedirs
>>> makedirs('somewhere', mode=0o0755)
>>> 
λ stat somewhere
  File: somewhere
  Size: 4096            Blocks: 8          IO Block: 4096   directory
Device: 804h/2052d      Inode: 19141748    Links: 2
Access: (0755/drwxr-xr-x)  Uid: ( 1000/    eric)   Gid: ( 1000/    eric)
Access: 2023-06-06 14:47:15.152311228 +0200
Modify: 2023-06-06 14:47:15.152311228 +0200
Change: 2023-06-06 14:47:15.152311228 +0200
 Birth: 2023-06-06 14:47:15.152311228 +0200
λ  rmdir somewhere
λ 

The only difference is that I created somewhere and not /somewhere. Are you doing this as super-user?

Thank you so much @Gribouillis to have tried !

Quote:Are you doing this as super-user?

no, but I just tried with super-user also and it give me the same 750 instead of 755.

I suppose it's linked to my umask ?

Yes it's linked to the umask, is there a way to not apply the umask ?

Meanwhile I do a chmod afterward,

but it so weird ! where I do a stat after the chmod I got 0755 as expected.

but when I display the Permissions trough Thunar I get

(Jun-06-2023, 01:15 PM)SpongeB0B Wrote: [ -> ]Yes it's linked to the umask, is there a way to not apply the umask ?

You could perhaps call os.umask() with suitable arguments? Try this to see the umask

Output:
λ python -c "import os; print(os.umask(0))"
2

Thanks @Gribouillis !

I'm shocked the documentation about os.umask() is quite not explanatory !

So according to the documentation
Set the current numeric umask and return the previous umask.

print(os.umask(0))

Should not only display the umask but also set it !?

(Jun-15-2023, 07:47 AM)SpongeB0B Wrote: [ -> ]Should not only display the umask but also set it !?

I just wanted to show the default value of the umask on my system. I chose the value 0 at random. Choose the value that you actually need for your file operation.

In the linux console, the current umask can also be displayed by invoking the umask command without argument

Output:
λ umask
0002

You could perhaps try

os.umask(os.umask(0) & ~(0o005))

to make sure that the umask does not prevent the "others" permission 5, or even

os.umask(os.umask(0) & ~(0o0755))

to make sure that the umask doesn't disallow the mode 0755