from this function:
def test(arg)
a = 0
if arg >3:
a=1
return a how do i use it in another function?:
def main():
arg = rand.randrange(0,7)
test(arg)
if a = 1:
print('I don't know what i'm doing')
Pass as an attribute
>>> def func1():
... return 15
...
>>> def func2(value):
... print('Value x 2 = {}'.format(value * 2))
...
>>> def main():
... a = func1()
... func2(a)
...
>>> main()
Value x 2 = 30
based on your code:
import random
def test(arg):
if arg > 3:
a = 1
else:
a = 0
return a
def main():
arg = random.randrange(0,7)
a = test(arg) # here you can use any name, not neccessary to be a
if a == 1:
print("I don't know what i'm doing")more pythonic would be
import random
def test(arg):
return arg >3
def main():
arg = random.randrange(0,7)
if test(arg):
print("I don't know what i'm doing")also note the double quotes of the string - otherwise you need to escape the single quotes
so in my case it would be:
def test(arg)
a = 0
if arg > 5:
a = 1
return a
def main():
arg = random.randrange
z = test(arg)
if z ==1:
Print('Will this work?')Thank both of you , now i think i can grasp functions.
(Sep-30-2017, 08:16 PM)Rius2 Wrote: [ -> ]so in my case it would be:
arg = random.randrange
Well, no. You never call random.randrange, so
arg is just a reference to the function itself. So "Will this work" should never be printed.
Any function returns an object which you can assign to a variable.
So you define one. Simplified because I am lazy today:
def test(arg):
return a
Then define another:
def second(some_argument):
b = test(some_argument)
if b != 'stupid example':
return 'Good enough'
Now call 'second':
s = 'No?'
second(s)
You can pass any argument to a function and use it inside another one. some_argument could be any python object, however, it is called. Of course, its type has to be suitable to use it at all.