Python Forum

As part of a quiz in Python, we were asked to create a for loop that would then print all elements of the string that begin with or end with the letter "z". I can only get the first [0] or last [-1] o print but not both.

latest attempt prints only pizazz

words = ["pizazz", "python", "zebra", "pizza"]
for word in words:
    if word[0] and word [-1] in "z":
        print word

Do I need another if statement or what is the correct syntax?

see https://python-forum.io/Thread-Multiple-...or-keyword

Thanks.

Never mind. Figured out I needed the second "if"

(Oct-05-2017, 11:43 AM)kekulpac Wrote: [ -> ]Never mind. Figured out I needed the second "if"

No, you don't need second if. your current condition word[0] and word [-1] in "z" is incorrect because word[0] is always evaluated to True, so it is in fact True and word [-1] in "z"

Also, you should use == instead of in given that you compare with single char 'z'

You need to test for either condition using an OR, or check if z is within a concatenated string:

Output:
>>> word="abcdefghj"
>>> word[0] == "z" or word[-1] == "z"
False
>>> "z" in word[0]+word[-1]
False
>>>
>>> word="abcdefghjz"
>>> word[0] == "z" or word[-1] == "z"
True
>>> "z" in word[0]+word[-1]
True
>>>
>>> word="zabcdefghj"
>>> word[0] == "z" or word[-1] == "z"
True
>>> "z" in word[0]+word[-1]
True