# [ ] use a "forever" while loop to get user input of integers to add to sum,
# until a non-digit is entered, then break the loop and print sum
sum = 0
the best I was able to think up doesn't work
while True:
sum = ''
sum1 = input("add number: ")
if sum1.isdigit():
sum = sum + sum1
else:
break
print(sum)Suggestions are welcome.
untested:
while True:
sum = 0
sum1 = input("add number or 'Q' to quit: ")
if sum1 == 'Q':
break;
if sum1.isdigit():
sum = sum + int(sum1)
else:
print('Please enter a digit!')
Below sum = sum + int(sum1) I added print(sum) but it's printing only the last input, not the sum. Not sure why.
just to mention that sum is a built-in function and should not be used as variable name - as is your code now you overwrite sum and the built-in function is no longer available
(Jan-19-2018, 12:14 PM)buran Wrote: [ -> ]just to mention that sum is a built-in function and should not be used as variable name - as is your code now you overwrite sum and the built-in function is no longer available
Here are all the built-in functions:
https://docs.python.org/3/library/functions.html
Look at them.
(Jan-19-2018, 12:02 AM)Larz60+ Wrote: [ -> ]show new code
while True:
suma = 0
sum1 = input("add number or 'Q' to quit: ")
if sum1 == 'Q':
break;
if sum1.isdigit():
suma = suma + int(sum1)
else:
print('Please enter a digit!')New it just repeats input request.
Each time the code is repeated in the loop, suma gets set to 0. You will need to put suma = 0 outside of while loop.
Sure it prints only input request. There is no print statement in the "if" that would print anything, until next loop iteration.
suma = 0
while True:
sum1 = input("add number or 'Q' to quit: ")
if sum1 == 'Q':
break;
if sum1.isdigit():
suma = suma + int(sum1)
print(suma)
else:
print('Please enter a digit!')This code works as I wanted!
Glad you did it, and thanks for posting solution!