Python Forum

Hi all,

I need your help with my code. I want to add the next day date using with time.struct_time object, but I have got no idea how to do this after I have stored the string in the self.epg_time_1 list.

Example:

time.struct_time(tm_year=2018, tm_mon=2, tm_mday=22, tm_hour=17, tm_min=00, tm_sec=0, tm_wday=3, tm_yday=53, tm_isdst=-1)

To this:

time.struct_time(tm_year=2018, tm_mon=2, tm_mday=23, tm_hour=17, tm_min=00, tm_sec=0, tm_wday=3, tm_yday=53, tm_isdst=-1)

If I want to add the next day, I would have to readd the same code that I have already been using:

epg_time_1_days = time.strftime("%d")
epg_time_1_months = time.strftime("%m")
epg_time_1_year = time.strftime("%Y")
epg_time_1_days = int(time.strftime("%d") + 1)
epg_time_1_days = str(today_day)
epg_time_1_months = str(epg_time_1_months)
epg_time_1_year = str(epg_time_1_year)
half_hour_date = str(epg_time_1_days + "/" + epg_time_1_months + "/" + epg_time_1_year + " " + "17:30PM")
self.epg_time_1.append(half_hour_date)

Here is the code:

half_hour_date = ''.join(str(x) for x in self.epg_time_1)
epg_time_1 = time.strptime(half_hour_date, '%d/%m/%Y %I:%M%p')

Output for half_hour_date:

22/02/2018 5:00PM

Output for epg_time_1:

[python]time.struct_time(tm_year=2018, tm_mon=2, tm_mday=22, tm_hour=17, tm_min=00, tm_sec=0, tm_wday=3, tm_yday=53, tm_isdst=-1)

I don't want to re-add the same code that I have already wrote it. If you can show me an example how I could use a short simple code to add the date to the next day date using with time.struct_time object, that would be great.

Thanks in advance

The following from: https://pymotw.com/3/datetime/

Date math uses the standard arithmetic operators.
datetime_date_math.py

import datetime

today = datetime.date.today()
print('Today    :', today)

one_day = datetime.timedelta(days=1)
print('One day  :', one_day)

yesterday = today - one_day
print('Yesterday:', yesterday)

tomorrow = today + one_day
print('Tomorrow :', tomorrow)

print()
print('tomorrow - yesterday:', tomorrow - yesterday)
print('yesterday - tomorrow:', yesterday - tomorrow)

This example with date objects illustrates using timedelta objects to compute new dates, and subtracting date instances to produce timedeltas (including a negative delta value).

Output:
$ python3 datetime_date_math.py

Today    : 2017-07-30
One day  : 1 day, 0:00:00
Yesterday: 2017-07-29
Tomorrow : 2017-07-31

tomorrow - yesterday: 2 days, 0:00:00
yesterday - tomorrow: -2 days, 0:00:00

Thank you very much for this, the problem are now being solved.