Quick Lists Question (Count Occurences)

[EwH006]

Good Evening,

I'm stuck in a headache and am looking to get some solutions. I've been given a problem that wants me to input 9 integers, and list the occurrences of those 9 integers. I've done it one way but the tool our class uses called 'Livelab' doesn't accept the code I gave it. For this purpose I will show both source code.


For the rejected code I used: 

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from collections import Counter a = [2, 5, 6, 5, 4, 3, 23, 43, 2] print(Counter(a))

The code I'm working on currently looks like this. I've got some of the print statements to work within Idle, but am having trouble and the book I have has been little help.

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for i in range(9):    num_list = int(input("Enter integers between 1 and 100: ")) print(num_list.count(2)) print(num_list.count(5)) print(num_list.count(6)) print(num_list.count(4)) print(num_list.count(3)) print(num_list.count(23)) print(num_list.count(43))

Any help would be appreciated!

[Larz60+]

On the numbers:
input all nine with one input statement:

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my_numbers = input('Enter 9 numbers separated by spaces') mn = my_numbers.split(' ') if len(mn) <> 9):     # Show error Do it again

Don't put that in a loop

[EwH006]

That isn't in python 3, or at least my interpret is saying it isn't. I'm talking about the <>.

I messed with that code a little bit though. That's not what I'm looking to do. I'm looking to input 9 numbers and after that count how many times each number occurs within that list.

[metulburr]

the easiest way to check occurrence if you cant use collections is to use a dictionary. The key as the identifyer (such as your 9 ints), and the value is the number of occurrences. Every time the dict key is inputed (one of your 9 ints), that key's value gets incremented.

[EwH006]

I still am not getting where I need to be. The console is supposed to spit out how many times each integer I input occurs. I've altered my code a bit since last post. I'm working with what I had before now and this:

lst = []
print("Enter 9 numbers: ")
for i in range(9):
lst.append(eval(input()))
print(lst.count())

[ichabod801]

Metulburr gave you the information you need to solve the problem. Don't use a list, use a dictionary. Have the key be the value inputted, and the value be the count. Increment the count each time you encounter a given input number. The only trick is to get the initial value for each number. You can do that with 'if key in dict:', although it is more common to use the get method of the dictionary.

And use code tags.

[heiner55]

Some tiny changes:

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from collections import Counter   lst = [] print("Enter 9 numbers: ") for i in range(9):     lst.append(int(input()))   print(Counter(lst))

[metulburr]

done it one way but the tool our class uses called 'Livelab' doesn't accept the code

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from collections import Counter   a = [2, 5, 6, 5, 4, 3, 23, 43, 2] print(Counter(a))

I thought you couldnt use collections?

[heiner55]

This works also:

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from collections import Counter my_numbers = input('Enter 9 numbers separated by spaces: ') lst = my_numbers.split(' ') if len(lst) != 9:     print("error: less or more than 9 numbers")   print(Counter(lst))

[nilamo]

I thought you couldnt use collections?

That's not OP.