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+--- Thread: Potential confusion combining != with or (/thread-22102.html)
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RE: Potential confusion combining != with or - Mark17 - Nov-04-2019
(Oct-31-2019, 07:21 AM)perfringo Wrote: buran explanation backed-up with Python docs (already referenced earlier):
Quote:Operations and built-in functions that have a Boolean result always return 0 or False for false and 1 or True for true, unless otherwise stated. (Important exception: the Boolean operations or and and always return one of their operands.)
This behaviour enables writing 'clever' code like:
>>> lst = [1, 2, 3] >>> for i in lst: ... print(i % 2 and 'odd' or 'even') ... odd even odd
I didn't see these three posts until now. This is the sort of explanation I really wanted except I do not understand. Can you explain the odd, even, odd output in this example?
RE: Potential confusion combining != with or - buran - Nov-04-2019
maybe this will help as it brakes line 3 into sub-steps
lst = [1, 2, 3]
for i in lst:
print(f'i={i}')
print(f"i % 2 --> {i % 2}")
print(f"{i % 2} and 'odd' --> {i % 2 and 'odd'}")
print(f"{i % 2 and 'odd'} or 'even' --> {i % 2 and 'odd' or 'even'}")
print('-'*10)Output:i=1
i % 2 --> 1
1 and 'odd' --> odd
odd or 'even' --> odd
----------
i=2
i % 2 --> 0
0 and 'odd' --> 0
0 or 'even' --> even
----------
i=3
i % 2 --> 1
1 and 'odd' --> odd
odd or 'even' --> odd
----------