+- Python Forum (https://python-forum.io)
+-- Forum: Python Coding (https://python-forum.io/forum-7.html)
+--- Forum: Homework (https://python-forum.io/forum-9.html)
+--- Thread: Help with loop (/thread-6515.html)
Pages:
1
2
RE: Help with loop - buran - Nov-26-2017
you should use string formatting
for nr in range(0, 100):
print('{: >2}'.format(nr), end=" ")
if nr % 10 == 9:
print()
RE: Help with loop - thanikos - Nov-27-2017
(Nov-26-2017, 09:30 PM)buran Wrote: you should use string formatting
for nr in range(0, 100): print('{: >2}'.format(nr), end=" ") if nr % 10 == 9: print()
Thank you buran !
RE: Help with loop - DeaD_EyE - Nov-27-2017
The use of modulo is clever. Here a solution with a nested loop, which is the naive way:
for j in range(0, 100, 10):
for i in range(j, j + 10):
print('{:>2}'.format(i), end=' ')
print()The outer loop counts from 0 to 90 with a step size of 10.So we get in the outer loop: 0, 10, 20, 30, 40, 50, 60, 70, 80, 90
The inner loop counts from j to j + 10.
The inner loop is iterating with following range objects:
[range(0, 10), range(10, 20), range(20, 30), range(30, 40), range(40, 50), range(50, 60), range(60, 70), range(70, 80), range(80, 90), range(90, 100)]In other words: The outer loop is representing the rows and the inner loop is representing the columns.
The modulo operator in the other examples is using the fact, that 9 % 10 == 9, 19 % 10 == 9, 29 % 10 == 9...
RE: Help with loop - Mekire - Nov-27-2017
(Nov-26-2017, 09:30 PM)buran Wrote: you should use string formattingfor nr in range(0, 100):
print('{: >2}'.format(nr), end=" ")
if nr % 10 == 9:
print()Way too readable.for nr in range(100):
print("{:02}".format(nr), end="\n" if nr % 10 == 9 else " ")