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Compare dictionaries in list - vaison - May-08-2018
Hello,
I have a list of dictionaries and I need to compare some values of all of them.
I only need to know if all of the comparison values are different or not.
I need to know if any 'name' in the dictionaries is repeated:
l1 = [{'name': 'n3', 'count':1, 'other':0}, {'name': 'n2', 'count':2}, {'name': 'n3', 'count':3, 'other': 0, 'other2':25 }]The answer in this case is "Yes" because the first and the third dictionaries in the list has the same 'name'.I try to get the dict values that I need to compare in lists, and then realize the comparative. But not work:
names = [l1[i]['name'] for i in range(len(l1))]I'm practicing my English to improve it. Then, I hope that I explained it well.
To consider:
- Initially, I don't know how many elements are in the list l1. The solution should work with any amount of dictionaries.
- The keys of the items to compare ('name' in this case) exists in all the dictionaries in the list
Is there a compact way to make this comparison, which can be used for lists with any number of dictionaries?
Thanks!
RE: Compare dictionaries in list - killerrex - May-08-2018
Use a set that will collect only the different values:
names = {d['name'] for d in l1}
if len(names) == len(l1):
print("All the names are different!")
else:
print("At least one name is repeated")
RE: Compare dictionaries in list - vaison - May-10-2018
Hi killerrex,
Great! Thanks a lot.