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+--- Thread: syntax error (/thread-11180.html)
syntax error - judin - Jun-26-2018
print("age restriction")
age=int(input("pls enter your age:"))
if age<=18:
print("access restricted for users below 19")
else:
print("access granted")
print("enter your name")
name1=(input("enter name: "))
print("welcome",name1)
access=int(input("if you already signed up press 1 , if you are a new user press 2")
if access=1:
username=(input("enter username"))
access=(input("enter pswd"))
print("welcome",username)
else:
print("go to link and pls register")
input("press any key to exit")
Invalid syntax error popup is displayed in 2nd if statement when i am trying to run this programe
pls help me out asap i have just stared to learn programming
thankyou
RE: syntax error - j.crater - Jun-26-2018
Please put your code in Python code tags and full error traceback message in error tags. You can find help here.
RE: syntax error - j.crater - Jun-26-2018
Oh well, error in your case is pretty simple (I didn't even take a closer look at first)... this line:
if access=1:means assignment (single equality sign), while you want to use == to check for equality.
Also, if you compare to '1' instead of 1, you don't even need to cast input to integer, but that's a detail.
RE: syntax error - judin - Jun-27-2018
Hi j.crater
thanks for your help
i am new to programming