Unable to convert XML to JSON - Printable Version +- Python Forum (https://python-forum.io) +-- Forum: Python Coding (https://python-forum.io/forum-7.html) +--- Forum: Web Scraping & Web Development (https://python-forum.io/forum-13.html) +--- Thread: Unable to convert XML to JSON (/thread-11226.html) |
Unable to convert XML to JSON - priyanka - Jun-29-2018 I have tried to convert a Url link which contains XML file to JSON but unable to do it. import urllib2 import json import xmltodict response.xml = urllib2.urlopen('https://www.openhub.net/projects.xml?api_key=xxxxxxx') with open("response.xml",'r') as f: xmlString = f.read() jsonString = json.dumps(xmltodict.parse(xmlString), indent=4) print(jsonString)This is the code I have used. I am getting the following error.
RE: Unable to convert XML to JSON - snippsat - Jun-29-2018 You probably use Python 3 as you should There also a problem,most also write the xml file before read it. import urllib.request import json import xmltodict xml = urllib.request.urlopen('https://www.openhub.net/projects.xml?api_key=xxxxxxxxxxxxxx') with open("response.xml", 'wb') as f_out: f_out.write(xml.read()) with open("response.xml", 'r') as f: xmlString = f.read() jsonString = json.dumps(xmltodict.parse(xmlString), indent=4) print(jsonString)Ideally don't use urllib at all,but Requests. import requests import json import xmltodict xml = requests.get('https://www.openhub.net/projects.xml?api_key=xxxxxxxxxxxxxx') with open("response.xml", 'wb') as f_out: f_out.write(xml.content) with open("response.xml", 'r') as f: xmlString = f.read() jsonString = json.dumps(xmltodict.parse(xmlString), indent=4) print(jsonString) |