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+--- Thread: Why is this the output I am getting? (/thread-11353.html)
Why is this the output I am getting? - wlsa - Jul-04-2018
def func_a():
print('inside func_a')
def func_c(z):
print('inside func_c')
return z()
print(func_c(func_a))the output I get isinside func_c
inside func_a
None
I'm having a hard time understanding how putting a function as an input into another function gives me this output.
RE: Why is this the output I am getting? - ichabod801 - Jul-04-2018
You pass func_a to func_c without calling it. func_c prints, and then calls the function that was passed to it (z()). So that calls func_a, which prints. func_a returns None (the default return value) to func_c, which does nothing. func_c returns None to the print function on line 6, and it gets printed.