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+--- Thread: Download all secret links from a map design website (/thread-11765.html)
Download all secret links from a map design website - fyec - Jul-24-2018
There is a website which shows links on a map (map layer currently can't be shown but links can be shown as points).
To view this website, this must be followed: (Pictures 1-2-3-4 also show the way)
Firstly, click this website 'http://svtbilgi.dsi.gov.tr/Sorgu.aspx', Picture 1
Secondly, choose '15. Kizilirmak Havzasi' from 'Havza' tab, Picture 2
Finally, click 'sorgula' bottom. Picture 3
After the final stage, you should view the website ('http://svtbilgi.dsi.gov.tr/HaritaNew.aspx') where the points can be shown on a map. Picture 4
Normally, I can use selenium to download webpages or can grab all links using different libraries. However, these methods can't obtain the links because they are embedded almost in a secret way.
I would like to download all links that these points have.
How can I get them?
from selenium import webdriver
from selenium.webdriver.support.ui import Select
from selenium.webdriver.support.ui import WebDriverWait
driver = webdriver.Firefox(executable_path=r'D:\geckodriver.exe')
driver.get("http://svtbilgi.dsi.gov.tr/Sorgu.aspx")
driver.find_element_by_id("ctl00_hld1_cbHavza").click()
Select(driver.find_element_by_id("ctl00_hld1_cbHavza")).select_by_visible_text("15. Kizilirmak Havzasi")
driver.find_element_by_id("ctl00_hld1_cbHavza").click()
driver.find_element_by_id("ctl00_hld1_btnListele").click()
parent_handle = driver.current_window_handle
all_urls = []
all_images = driver.find_elements_by_xpath("//div[contains(@id,'OL_Icon')]/img")
for image in all_images :
image.click()
for handle in driver.window_handles :
if handle != parent_handle:
driver.switch_to_window(handle)
WebDriverWait(driver, 5).until(lambda d: d.execute_script('return document.readyState') == 'complete')
all_urls.append(driver.current_url)
driver.close()
driver.switchTo.window(parent_handle This script doesn't continue after 'parent_handle = driver.current_window_handle' line.