+- Python Forum (https://python-forum.io)
+-- Forum: Python Coding (https://python-forum.io/forum-7.html)
+--- Forum: General Coding Help (https://python-forum.io/forum-8.html)
+--- Thread: pow function (/thread-12777.html)
pow function - luoheng - Sep-12-2018
hi,
I met a problem when using the built-in function pow().
here is the code:
In [1]: pow(-2, 1/3) Out [1]: (0.6299605249474367+1.0911236359717214j) In [2]: (-2) ** 1/3 Out [2]: -0.6666666666666666The document says pow(x, y) is equivalent to x ** y, but it is different here.
Why??
I use python3.6, anaconda Spyder.
RE: pow function - Gribouillis - Sep-12-2018
Operator precedence implies that
>>> (-2) ** 1/3 == ((-2) ** 1)/3 Truewhich is different from
(-2) ** (1/3)