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+--- Forum: General Coding Help (https://python-forum.io/forum-8.html)
+--- Thread: Dictionary Help (/thread-1286.html)
Dictionary Help - sajley - Dec-20-2016
hi guys
mydict = {'transform':[4,52,6.3] , 'rotation':[77,89,12] , 'scale':[44,55,96]}mydict['scale']
Output:[44,55,96]
i learn python for CG & VFX , i need to define (for example) 'scale' [x,y,z] , how i can access to x or y or z, in dictionary.
RE: Dictionary Help - wavic - Dec-20-2016
The same way you access a list items.
In [1]: mydict = {'transform':[4,52,6.3] , 'rotation':[77,89,12] , 'scale':[44,55,96]}
In [2]: mydict['scale'][2]
Out[2]: 96
RE: Dictionary Help - sajley - Dec-20-2016
(Dec-20-2016, 07:43 PM)wavic Wrote: The same way you access a list items.
In [1]: mydict = {'transform':[4,52,6.3] , 'rotation':[77,89,12] , 'scale':[44,55,96]} In [2]: mydict['scale'][2] Out[2]: 96
thankyou
what is: in & out ???
in[1] , out[2]
in[1]: in[2]: out[2]:
RE: Dictionary Help - Larz60+ - Dec-20-2016
To get the value:
z = mydict['scale'][2] print(z)To see if the value is in any dict entry:
mydict = {
'transform': [4, 52, 6.3],
'rotation' : [77, 89, 12],
'scale': [44, 55, 96]
}
for key, value in mydict.items():
if 96 in value:
print('found 96 in: {}'.format(key))
RE: Dictionary Help - wavic - Dec-20-2016
It's just a Python interpreter prompt. Like '>>>' in the usual Python interpreter. It's called IPython and it's awesome.
See this: https://www.youtube.com/watch?v=vrdYvjGTrQA
RE: Dictionary Help - sajley - Dec-20-2016
thanks to all, Worked. :)))))