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I got a problem with python schedule - Printable Version

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I got a problem with python schedule - darktitan - Sep-22-2018

Hi im trying to make an time triggered event with schedule where i can inpute a time and then activate the clock after a couple of seconds something would happen but my code is giving me an error.

Error:
Traceback (most recent call last):
  File "C:\Users\xzenon\Desktop\timmer\time2.py", line 29, in ok_handler
    schedule.every(sekunderValue).seconds.do(self.job)
  File "C:\Users\xzenon\AppData\Local\Programs\Python\Python37-32\lib\site-packages\schedule\__init__.py", line 393, in do
    self._schedule_next_run()
  File "C:\Users\xzenon\AppData\Local\Programs\Python\Python37-32\lib\site-packages\schedule\__init__.py", line 428, in _schedule_next_run
    self.period = datetime.timedelta(**{self.unit: interval})
TypeError: unsupported type for timedelta seconds component: str
So what am i doing wrong?

Here is my code.

import sys
import schedule
 
from PySide2.QtUiTools import QUiLoader
from PySide2.QtWidgets import QApplication, QPushButton, QLineEdit
from PySide2.QtCore import QFile, QObject
 
class Form(QObject):
 
    def __init__(self, ui_file, parent=None):
        super(Form, self).__init__(parent)
        ui_file = QFile(ui_file)
        ui_file.open(QFile.ReadOnly)
 
        loader = QUiLoader()
        self.window = loader.load(ui_file)
        ui_file.close()
 
        self.sekunder = self.window.findChild(QLineEdit, 'sekunder')
 
        btn = self.window.findChild(QPushButton, 'pushButton')
        btn.clicked.connect(self.ok_handler)
        self.window.show()
 
    def ok_handler(self):
        sekunderValue = self.sekunder.text()
        
        print(sekunderValue)
        schedule.every(sekunderValue).seconds.do(self.job)
        
        while 1:
           schedule.run_pending()
           time.sleep(1)
           
        
    def job(self):
       print("I'm working...")
       
if __name__ == '__main__':
    app = QApplication(sys.argv)
    form = Form('timmer.ui')
    sys.exit(app.exec_())


RE: I got a problem with python schedule - stullis - Sep-22-2018

So, the traceback shows that the method call on line 29 ultimately results in an error because a string has been passed instead of an integer. From what I see, the suspect variable you're passing in is "sekunderValue" which is set on line 26:

sekunderValue = self.sekunder.text()
The method .text() suggests to me that it returns a string. If that is intended to be an integer, you need to do this instead for the ok_handler method:

    def ok_handler(self):
        sekunderValue = int(self.sekunder.text())
         
        print(sekunderValue)
        schedule.every(sekunderValue).seconds.do(self.job)
         
        while 1:
           schedule.run_pending()
           time.sleep(1)


RE: I got a problem with python schedule - darktitan - Sep-22-2018

Thank you