Help with nested dictionary - Printable Version

Help with nested dictionary - Printable Version

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Help with nested dictionary - Anidil - Sep-24-2018

myStr = '''Ethernet Channel Bonding Driver: v3.7.1 (April 27, 2011)

Output:Bonding Mode: IEEE 802.3ad Dynamic link aggregation
Transmit Hash Policy: layer2+3 (2)
MII Status: up
MII Polling Interval (ms): 100
Up Delay (ms): 0
Down Delay (ms): 0

802.3ad info
LACP rate: slow
Min links: 0
Aggregator selection policy (ad_select): stable
Active Aggregator Info:
        Aggregator ID: 2
        Number of ports: 2
        Actor Key: 11
        Partner Key: 705
        Partner Mac Address: 02:1c:73:9c:3c:fe

Slave Interface: p1p1
MII Status: up
Speed: 10000 Mbps
Duplex: full
Link Failure Count: 0
Permanent HW addr: 9c:dc:71:45:eb:80
Aggregator ID: 2
Slave queue ID: 0

Slave Interface: p4p1
MII Status: up
Speed: 10000 Mbps
Duplex: full
Link Failure Count: 0
Permanent HW addr: 9c:dc:71:4d:80:20
Aggregator ID: 2
Slave queue ID: 0'''

I have the above text outputs and I want to create a nested dictionary as follows:

bond0 : {
         'MII Status:' : 'up',
         'Aggregator ID:' : '2',
          'Slave Interfaces' : { 'p1p1' : { 'MII Status' : 'up',
                                             'Permanent HW addr' : '9c:dc:71:45:eb:80',
                                             'MII Status' : up },
                                 'p4p1' : { ''MII Status' : 'up',
                                             'Permanent HW addr' : '9c:dc:71:4d:80:20',
                                             'MII Status' : up },
                                 },

I began doing some coding as shown below, but still not getting there :

from __future__ import print_function

class BndClass(dict):
    def __init__(self, Bnd=None):
        self['Name'] = Bnd
        self.uPdateInfo()
        super(BndClass, self).__init__()

    def uPdateInfo(self):
        
        for line in myStr.splitlines():
            match = re.search(r'^Cur.*?:\s+(.*?)$', line)
            if match:
                self['act_int'] = match.group(1)

            match = re.search(r'^\s*?Aggregator ID:\s+(\d)$', line)
            if match:
                self['agid'] = match.group(1)

            match = re.search(r'^Slave\sInterface:\s(.*?)$', line)
            if match:
                self.setdefault('slvs', []).append(match.group(1))

if __name__ == '__main__':
Y = BndClass('bond0')
Y
{'Name': 'bond0', 'agid': '2', 'slvs': ['p1p1', 'p4p1']}

please help

RE: Help with nested dictionary - Larz60+ - Sep-24-2018

I added code tags for you.
It's so much easier to read a dictionary if written like:

bond0: {
    'MII Status:': 'up',
    'Aggregator ID:': '2',
    'Slave Interfaces': {
        'p1p1': {
            'MII Status': 'up',
            'Permanent HW addr': '9c:dc:71:45:eb:80',
            'MII Status': up
        },
        'p4p1': {
            'MII Status' : 'up',
            'Permanent HW addr': '9c:dc:71:4d:80:20',
            'MII Status': up
        }
    }
}

you can use something like the following to traverse a nested dictionary:

def display_dict(thedict):
    for key, value in thedict.items():
        if isinstance(value, dict):
            print(f'{key}:')
            self.display_dict(value)
        else:
            print(f'    {key}: {value}')

display_dict(bond0)

This also corrects errors you had in your definition