regex help to get the local ip address

regex help to get the local ip address - Printable Version

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regex help to get the local ip address - evilcode1 - Sep-26-2018

hey all... need a help in regex ..

im trying to get the local ip address form a windows system by running this code : ( i dont want to use python socket )

import os
import re

q = os.popen("""ipconfig | findstr /R /C:"IPv4 Address""").read()
print q 
dev = re.findall('[0-9]+' , q)
print dev

the result is : ['4', '192', '168', '74', '163']
the cmd result is : IPv4 Address. . . . . . . . . . . : 192.168.74.163

i need to get just this result : 192.168.74.163
how i can do it by regex ??

thanks in advance

RE: regex help to get the local ip address - evilcode1 - Sep-26-2018

solved :

from os import popen
from re import findall

q = popen("""ipconfig | findstr /R /C:"IPv4 Address""").read()
print q 
dev = findall( r'[0-9]+(?:\.[0-9]+){3}' , q)
print dev[0]

RE: regex help to get the local ip address - Axel_Erfurt - Sep-26-2018

import socket
print([l for l in ([ip for ip in socket.gethostbyname_ex(socket.gethostname())[2] if not ip.startswith("127.")][:1], [[(s.connect(('8.8.8.8', 53)), s.getsockname()[0], s.close()) for s in [socket.socket(socket.AF_INET, socket.SOCK_DGRAM)]][0][1]]) if l][0][0])

RE: regex help to get the local ip address - evilcode1 - Sep-26-2018

(Sep-26-2018, 12:15 PM)Axel_Erfurt Wrote:

import socket
print([l for l in ([ip for ip in socket.gethostbyname_ex(socket.gethostname())[2] if not ip.startswith("127.")][:1], [[(s.connect(('8.8.8.8', 53)), s.getsockname()[0], s.close()) for s in [socket.socket(socket.AF_INET, socket.SOCK_DGRAM)]][0][1]]) if l][0][0])

thank u very much dear

RE: regex help to get the local ip address - nilamo - Sep-26-2018

>>> import re
>>> response = 'IPv4 Address. . . . . . . . . . . : 192.168.74.163 '
>>> match = re.search(r'((\d+\.?){4})', response)
>>> match.groups()
('192.168.74.163', '163')

But what happens if it's ipv6?