Python Forum
[split] [Help] Keep getting a 'TypeError' from Django and BeautifulSoup - Printable Version

+- Python Forum (https://python-forum.io)
+-- Forum: Python Coding (https://python-forum.io/forum-7.html)
+--- Forum: Web Scraping & Web Development (https://python-forum.io/forum-13.html)
+--- Thread: [split] [Help] Keep getting a 'TypeError' from Django and BeautifulSoup (/thread-14111.html)

[split] [Help] Keep getting a 'TypeError' from Django and BeautifulSoup - moxasya - Nov-15-2018

Hi. I am also new to Django. I want to do the same as you scrape using Django as a web application. the code right now working fine using python3 Jupyter notebook. 

import requests
import json
import time
from bs4 import BeautifulSoup as soup

def getLi(text):
    for i in x: 
        if i[0] == "i" and i[1:].isdigit():
            return (i.replace("i",""))
            
headers = {'user-agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/69.0.3497.100 Safari/537.36'}

count = 0
link = input("Please enter url to scrape ")
x = link.split("-")
d = soup(requests.get(link).text, 'html.parser')
results = list(map(int, filter(None, [i.text for i in d.find_all('button', {'class':'next-pagination-item'})])))
print (results)
for i in range(min(results), max(results)+1):
    count+=1
    time.sleep(10)  #0.5 * random.random()
    url = ('https://my.lazada.com.my/pdp/review/getReviewList?'
        'itemId='+str(getLi(x))+'&pageSize=5&filter=0&sort=0&pageNo='+str(count))
    print(url)
    req = requests.get(url,headers=headers)
    data = req.json()
    print(count)
    for i in data['model']['items']:
    
        reviewContent = i['reviewContent']
        
        print(reviewContent)
        print('------------------------------------------')
where should I put this code? models.py right? what should I put at views.py and templates folder that contain HTML. Huh Huh